MySQL的左連接自或類似

Question

我有這樣的查詢：

SELECT SUM(spend.price) AS total, WEEKDAY(spend.date) AS weekday 
FROM spend 
WHERE spend.date BETWEEN '2012-11-01' AND '2012-11-07' 
GROUP BY WEEKDAY(spend.date) ; 

眼下查詢給了我只有天中，用戶有一定的款項。

total weekday 
60 2 
10 3 
3  5 
3  6 

但是反而我想每天給我0（零）沒有付款。

total weekday 
0  1 
60 2 
10 3 
0  4 
3  5 
3  6 
0  7 

表格架構here。

Answer 1

原來這裏是語法：

SELECT SUM(spend.price) AS total, day AS weekday 
FROM (SELECT price, WEEKDAY(date) as day FROM spend WHERE date BETWEEN '2012-11-01' AND '2012-11-07' 
UNION ALL 
SELECT 0,0 
UNION ALL 
SELECT 0,1 
UNION ALL 
SELECT 0,2 
UNION ALL 
SELECT 0,3 
UNION ALL 
SELECT 0,4 
UNION ALL 
SELECT 0,5 
UNION ALL 
SELECT 0,6 
) spend 
GROUP BY day ; 

這裏是一個縮短：

CREATE TEMPORARY TABLE tmp (`price` int, `day` int); 
INSERT INTO tmp VALUES (0,0),(0,1),(0,2),(0,3),(0,4),(0,5),(0,6); 
SELECT SUM(spend.price) AS total, day AS weekday 
FROM (SELECT price, WEEKDAY(date) as day FROM spend WHERE date BETWEEN '2012-11-01' AND '2012-11-07' 
UNION ALL 
SELECT * FROM tmp 
) spend 
GROUP BY day ; 

這裏是一個演示：從你的子查詢http://sqlfiddle.com/#!2/8c323/3/0