ActiveRecord日期時間比較

我有日期時間

的out_date和in_date情況下，我有這個疑問：

reservations = Reservation.where("bookable_id = :bookable_id AND bookable_type = :bookable_type AND status <> :status AND ((:out_date >= check_out_date AND :out_date <= check_in_date) OR (:in_date <= check_in_date AND :in_date >= check_out_date) OR (:out_date <= check_in_date AND :in_date >= check_in_date))", :bookable_id => params[:bookable_id], :bookable_type => params[:bookable_type], :status => Reservation::STATUS_CHECKED_IN, :out_date => out_date, :in_date => in_date)

我總是空集，即使我應該得到回報的元組。

我嘗試了這些一些變體：

out_date.utc 

out_date.utc.to_s(:db)

一切似乎是工作。如何構建這個查詢？

控制器代碼：

in_date = DateTime.strptime params[:checkin], "%Y-%m-%d %H:%M" 
    out_date = DateTime.strptime params[:checkout], "%Y-%m-%d %H:%M" 

    #check collision with non-recurring reservations 
    reservations = Reservation.where("bookable_id = :bookable_id AND bookable_type = :bookable_type AND status <> :status AND ((:out_date >= check_out_date AND :out_date <= check_in_date) OR (:in_date <= check_in_date AND :in_date >= check_out_date) OR (:out_date <= check_in_date AND :in_date >= check_in_date))", :bookable_id => params[:bookable_id], :bookable_type => params[:bookable_type], :status => Reservation::STATUS_CHECKED_IN, :out_date => out_date, :in_date => in_date) 
    logger.info(reservations) 
    if !reservations.empty? 
    @error_message = "This Asset has already been reserved for those dates" 
    return 
    end

同樣在導軌控制檯，簡單的查詢失敗：

1.9.3p0 :007 > Reservation.find_by_id 31 
    Reservation Load (0.7ms) SELECT `reservations`.* FROM `reservations` WHERE `reservations`.`id` = 31 LIMIT 1 
=> #<Reservation id: 31, bookable_id: 11, bookable_type: "Asset", user_id: 1, check_out_date: "2012-07-07 08:00:00", check_in_date: "2012-07-07 10:00:00", notes: "rec", status: "Ready", is_recurring: true, repeat_count: 5> 


1.9.3p0 :009 > Reservation.where " ? >= check_out_date AND ? <= check_in_date",DateTime.new(2012,7,7,9),DateTime.new(2012,7,7,9) 
    Reservation Load (0.5ms) SELECT `reservations`.* FROM `reservations` WHERE ('2012-07-07 09:00:00' >= check_out_date AND '2012-07-07 09:00:00' <= check_in_date) 
=> []

來源

2012-07-04 Nitish Upreti

「out_date」變量分配在哪裏？ –

另外，你應該使用[命名範圍]（http://ar.rubyonrails.org/classes/ActiveRecord/NamedScope/ClassMethods.html）。 –

@SimoneCarletti在同一個控制器中。 –

這個錯誤是因爲數據庫時間以UTC存儲，本地時間不同而且不滿足查詢條件。

來源

2012-07-04 19:42:00

我讀了更新後的代碼，顯然，這是正確的。確保out_date和in_date是DateTime對象而不是空對象。

你不需要格式化查詢，它應該爲你處理。

如果要調試SQL查詢，您可以使用.to_sql

reservations = Reservation.where("...") # your query 
puts reservation.to_sql 
# => "SELECT ..."

打印查詢，並檢查值的格式正確無誤。

來源

2012-07-04 09:04:58

我得到這個：SELECT COUNT（*）FROM'reservations' WHERE（bookable_id ='11'AND bookable_type ='Asset'AND status <>'Checked In'AND（（''2012-07 -07 09:00:00'> = check_out_date AND'2012-07-07 09:00:00'<= check_in_date）或（'2012-07-07 11:00:00'<= check_in_date AND'2012-07 -07 11:00:00'> = check_out_date）或（'2012-07-07 09:00:00'<= check_in_date AND'2012-07-07 11:00:00'> = check_in_date））） –

This似乎很好。如果check_in_date和check_out_date由rails處理。爲什麼我沒有得到任何結果？ –

在這一點上，問題是查詢本身。嘗試從更簡單的查詢開始，然後添加一個條件並查看失敗的位置。 –

ActiveRecord日期時間比較

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