如何排序列表視圖陣列中的Android

Question

我有代碼，針對Android服務器獲取手機聯繫人菜單項，我用的菜單項，使吧，這是我的代碼

Cursor cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,null,null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC"); 
      int row = cursor.getCount(); 
      friend_item = new MenuItem [row]; 
      //int i=0; 

      while(cursor.moveToNext()){ 
       nama = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)); 
       phone = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
      // friend_item[i] = new MenuItem(nama,phone); 
       //i++; 
      } 

      cursor.moveToFirst(); 
      while(!cursor.isAfterLast()){ 
       Log.d("", "" + cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))); 
       phone = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
       phoneList.add(phone); 
       cursor.moveToNext(); 
      } 

      cursor.close();    

      String [] phonearray = (String[]) phoneList.toArray(new String[phoneList.size()]);   

     // friendarray(); 
      String friends=phonearray[0]+""; 
      for(int a=1; a<phonearray.length; a++){ 
       friends = friends + ","+ phonearray[a]; 

      } 

      Log.d("" , "" + friends);   
       List<NameValuePair> params = new ArrayList<NameValuePair>(); 
       params.add(new BasicNameValuePair("phone", mPhoneNumber)); 
       params.add(new BasicNameValuePair("friend", friends)); 

       // getting JSON string from URL 
       JSONObject json = jParser.makeHttpRequest(Constants.url_phone_contact, "POST", params); 

       // Check your log cat for JSON reponse 
       Log.d("All Friend: ", json.toString()); 

       try { 
        friend = json.getJSONArray("friend"); 
        friend_item = new MenuItem[friend.length()]; 
        // looping through All Products 
        for (int a = 0; a < friend.length(); a++) { 
        JSONObject c = friend.getJSONObject(a); 

        //Storing each json item in variable 

        phone_friend= c.getString("phone"); 
        id_friend = c.getString("id_ref"); 

        Log.e("id_user", id_friend); 


        namaFriend = getName(phone_friend);          

        if(phone_friend == null){ 
         Toast.makeText(getApplicationContext(), "contact not found", Toast.LENGTH_LONG).show(); 
        }else{ 
         friend_item[a] = new MenuItem(namaFriend, phone_friend); 

        // creating new HashMap 
        HashMap<String, String> map1 = new HashMap<String, String>(); 

        // adding each child node to HashMap key => value 
        //map1.put("phone", mPhoneNumber); 
        map1.put("id_ref", id_friend); 
        map1.put("nama_friend", namaFriend); 

        // adding HashList to ArrayList 
        friendList.add(map1); 

        } 
        } 

       } catch (JSONException e) { 

       e.printStackTrace(); 

       } 
       //i++;*/  

      return null;    
     }  

    /** 
     * After completing background task Dismiss the progress dialog 
     * **/ 
    protected void onPostExecute(String file_url) { 
      pDialog.dismiss();  
      if(friend_item != null && friend_item.length > 0){    

       mainlist.setAdapter(new ListMenuAdapter(friend_item)); 

      } else 
       Toast.makeText(getApplicationContext(), "You don't have friend using Shoop! yet, please invite them :)", Toast.LENGTH_LONG).show(); 
     } 
    } 

從Android設備獲得名，我用這個代碼

private String getName(String number) { 
     // define the columns I want the query to return 
     String[] projection = new String[] { 
       ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME, 
       ContactsContract.CommonDataKinds.Phone.NUMBER}; 

     // encode the phone number and build the filter URI 
     Uri contactUri = Uri.withAppendedPath(ContactsContract.CommonDataKinds.Phone.CONTENT_FILTER_URI, Uri.encode(number)); 

     // query time 
     Cursor c = getContentResolver().query(contactUri, projection, null, 
       null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME +" ASC"); 

     // if the query returns 1 or more results 
     // return the first result 
     if (c.moveToFirst()) { 
      String name = c.getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)); 
      return name; 
     } 

     // return the original number if no match was found 
     return number; 
    } 

名單菜單適配器

private class ListMenuAdapter extends BaseAdapter{ 

     private MenuItem [] item; 

     protected ListMenuAdapter(MenuItem... item){ 
      this.item = item; 
     } 

     public int getCount() { 
      return item.length; 
     } 

     public Object getItem(int pos) { 
      return item[pos]; 
     } 

     public long getItemId(int position) { 
      return position; 
     } 

     public ViewGroup getViewGroup(int position, View view, ViewGroup parent){ 
      if(view instanceof ViewGroup){ 
       return (ViewGroup) view; 
      } 

      Context context = parent.getContext(); 
      LayoutInflater inflater = LayoutInflater.from(context); 
      ViewGroup viewgroup = (ViewGroup)inflater.inflate(R.layout.custom_content_friend, null); 

      return viewgroup;   
     } 



     public View getView(int position, View convertView, ViewGroup parent) { 

      ViewGroup group = getViewGroup(position, convertView, parent); 
      MenuItem menu = item[position]; 

      TextView name = (TextView) group.findViewById(R.id.content_friend_myname); 
      TextView phone = (TextView) group.findViewById(R.id.content_friend_desc); 

      if(menu.my_name == null || menu.phone == null){ 
       Toast.makeText(getApplicationContext(), "Contact not found", Toast.LENGTH_LONG).show(); 
      }else{  
      name.setText(menu.my_name); 
      phone.setText(menu.phone); 
      } 

      return group;  
     }  
    } 

    private class MenuItem{ 

     private String my_name, phone; 

     protected MenuItem(String my_name, String phone){ 
      this.my_name = my_name; 
      this.phone= phone; 
     }  

    } 

，現在，我希望立刻得到包含n個列表視圖Ame和電話與排序按名稱升序，如何做到這一點？感謝烏拉圭回合的建議

Answer 1

在您的活動類寫：

public class MyActivity extends Activity { 

    .... 
    private ListView listView01; 
    private ArrayList<MenuItem> list; 

    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

    //  ... 
     listView01 = (ListView)findViewById(R.id.listView1); 

     list=new ArrayList<MyActivity.MenuItem>(); 

    // code to fill your ArrayList 

     Collections.sort(list, myComparator); 

     listView01.setAdapter(new ListMenuAdapter()); 
    } 
     Comparator<MenuItem> myComparator = new Comparator<MenuItem>() 
    { 
      public int compare(MenuItem arg0,MenuItem arg1) 
      { 
       return arg0.my_name.compareTo(arg1.my_name); 
      } 

}; 
} 

Answer 2

-首先使用的ArrayList代替Array存儲，這將進一步正在使用的適配器的數據。

-使用根據名稱java.util.Comparator<T>到排序的姓名和電話（即接觸）。

-使用Collections.sort(List<?> l , Comparator c)來調用排序。

-並且在用適配器設置ListView之後，還在適配器上調用notifyDataSetChanged()。

如：

import java.util.ArrayList; 
import java.util.Collections; 
import java.util.Comparator; 

class Car { 

    private String name; 
    private String brand; 
    private double cost; 

    public Car(String name, String brand, double cost) { 

     this.name = name; 
     this.brand = brand; 
     this.cost = cost; 
    } 

    public String getName() { 
     return name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    public String getBrand() { 
     return brand; 
    } 

    public void setBrand(String brand) { 
     this.brand = brand; 
    } 

    public double getCost() { 
     return cost; 
    } 

    public void setCost(double cost) { 
     this.cost = cost; 
    } 

    public String toString() { 

     return getName(); 
    } 

} 

public class Hog { 

    ArrayList<Car> cars = new ArrayList<Car>(); 

    public void setIt() { 

     cars.add(new Car("Padmini", "Fiat", 100008.00)); 
     cars.add(new Car("XYlo", "Mahindra", 100000.00)); 
     cars.add(new Car("Swift", "Maruti", 200000.00)); 
    } 

    public void sortIt() { 

     Collections.sort(cars, new NameComparator()); 
     System.out.println(cars); 
     Collections.sort(cars, new BrandComparator()); 
     System.out.println(cars); 
     Collections.sort(cars, new CostComparator()); 
     System.out.println(cars); 
    } 

    class NameComparator implements Comparator<Car> { 

     public int compare(Car c1, Car c2) { 

      return c1.getName().compareTo(c2.getName()); 
     } 
    } 

    class BrandComparator implements Comparator<Car> { 

     public int compare(Car c1, Car c2) { 

      return c1.getBrand().compareTo(c2.getBrand()); 
     } 
    } 

    class CostComparator implements Comparator<Car> { 

     public int compare(Car c1, Car c2) { 

      return new Double(c1.getCost()).compareTo(new Double(c2.getCost())); 
     } 
    } 

    public static void main(String[] args) { 

     Hog h = new Hog(); 

     h.setIt(); 
     h.sortIt(); 
    } 

}