0
我正在嘗試構建一個html表單並將其連接到正在執行查詢並將信息插入到mysql數據庫的php文件中。html表單tp php文件
這裏是我的html代碼:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add Record Form</title>
</head>
<body>
<form action="/joomla_31/insert.php" method="post">
<label for="MGMT_IP">MGMT IP</label>
<input type="text" name="MGMT_IP" id="MGMT_IP">
</p>
<p>
<label for="Vendor">Vendor</label>
<input type="text" name="Vendor" id="Vendor">
</p>
<p>
<label for="Version">Version</label>
<input type="text" name="Version" id="Version">
</p>
<p>
<label for="GUI_User">GUI User</label>
<input type="text" name="GUI_User" id="GUI_User">
</p>
<p>
<label for="GUI_Pass">GUI Pass</label>
<input type="text" name="GUI_Pass" id="GUI_Pass">
</p>
<input type="submit" value="submit">
</form>
</body>
</html>
,這裏是我的insert.php文件:
<?php
$link = mysqli_connect("localhost", "root", "", "mysql");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$MGMT_IP = mysqli_real_escape_string($link, $_REQUEST['MGMT IP']);
$Vendor = mysqli_real_escape_string($link, $_REQUEST['Vendor']);
$Version = mysqli_real_escape_string($link, $_REQUEST['Version']);
$GUI_User = mysqli_real_escape_string($link, $_REQUEST['GUI User']);
$GUI_Pass = mysqli_real_escape_string($link, $_REQUEST['GUI Pass']);
// attempt insert query execution
$sql = "INSERT INTO `cloud_team` (MGMT IP, Vendor, Version, GUI User, GUI Pass) VALUES (`$customer_number`, `$customer_name`, `$MGMT_IP`, `$Vendor`, `$Version`, `$GUI_User`, `$GUI_Pass`)";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// close connection
mysqli_close($link);
?>
但每次我點擊提交按鈕時,我得到一個空白頁... 這就像它是重定向正確的文件(http://x.x.x.x/joomla_31/insert.php)..但沒有執行...沒有錯誤顯示..只有一個空白頁
[如何啓用PHP錯誤顯示](https://stackoverflow.com/questions/1053424/how-do-i-get-php-errors-to-display) - 這可能有助於調試您的代碼 – lumio
謝謝lumio,我編輯php.ini文件從「display_errors = off」到「display_errors = on」 現在我收到此錯誤: 解析錯誤:語法錯誤,意外的''''(T_CONSTANT_ENCAPSED_STRING)在C:\ inetpub \ wwwroot \ joomla_31 \ joomla_31 \ insert.php在線23 –
看來,Joomla預計一些其他類型的參數 – lumio