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我正在構建一個簡單的字母計數應用程序,它需要從editText
輸入一個數字,並檢查這是否是textView(random name)
中的字母正確數量,單擊該按鈕時顯示正確的數字,如果正確的數字是輸入或不正確,每次顯示不正確。字符計數遊戲android
public class MainActivity extends AppCompatActivity {
EditText EditTextInput;
String strInput;
Button btn;
TextView txtLenght;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
EditTextInput= (EditText)findViewById(R.id.editText);
EditTextInput.getText().toString();
txtLenght = (TextView)findViewById(R.id.textView2);
txtLenght.getText().toString();
btn = (Button)findViewById(R.id.button);
btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (EditTextInput==txtLenght)
{
Toast.makeText(getApplicationContext(), "Your Guess is correct", Toast.LENGTH_LONG).show();
}
else {
Toast.makeText(getApplicationContext(), "Your Guess is wrong!!!", Toast.LENGTH_LONG).show();
}
};
});
}
非常感謝@Avijit Karmakar它的工作,但我不得不再次解析的onClick類中的整數才把它的工作,謝謝。 –