使用數組初始化結構數組作爲結構的元素

Question

我想初始化一個包含數組的結構數組。縱觀 this和 this， 我覺得一個非常合理的嘗試是這樣的：

struct Score_t{ 
    int * dice; 
    int numDice; 
    int value; 
}; 
struct Score_t Scores[NUMSCORES] = { 
    [0]={{0,0,0},3,1000}, 
    [1]={{1,1,1},3,200}, 
    [2]={{2,2,2},3,300}, 
    [3]={{3,3,3},3,400}, 
    [4]={{4,4,4},3,500}, 
    [5]={{5,5,5},3,600}, 
    [6]={{0},3,100}, 
    [7]={{4},3,50} 
}; 

但是我不能得到這個編譯。你有什麼辦法來完成這個任務嗎？

編輯：忘記錯誤信息：（剪斷）

[5]={{5,5,5},3,600}, 
^
greed.c:79:2: warning: (near initialization for ‘Scores[5].dice’) [enabled by default] 
greed.c:79:2: warning: initialization makes pointer from integer without a cast [enabled by default] 
greed.c:79:2: warning: (near initialization for ‘Scores[5].dice’) [enabled by default] 
greed.c:79:2: warning: excess elements in scalar initializer [enabled by default] 
greed.c:79:2: warning: (near initialization for ‘Scores[5].dice’) [enabled by default] 
greed.c:79:2: warning: excess elements in scalar initializer [enabled by default] 
greed.c:79:2: warning: (near initialization for ‘Scores[5].dice’) [enabled by default] 
greed.c:80:2: warning: braces around scalar initializer [enabled by default] 

Answer 1

int *不能{ }初始化（不匹配）
所以改變這樣。

struct Score_t Scores[NUMSCORES] = { 
    [0]={(int[]){0,0,0},3,1000}, 
    [1]={(int[]){1,1,1},3,200}, 
    [2]={(int[]){2,2,2},3,300}, 
    [3]={(int[]){3,3,3},3,400}, 
    [4]={(int[]){4,4,4},3,500}, 
    [5]={(int[]){5,5,5},3,600}, 
    [6]={(int[]){0},3,100}, //It doesn't know the number of elements 
    [7]={(int[]){4},3,50} //change to [7]={(int[3]){4},3,50} or [7]={(int[]){4},1,50} 
};