如何在每次調用返回不同的輸出到模擬的方法

Question

我跨張貼這question I asked MATLAB的答案。

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我想使用新的MATLAB嘲笑框架來測試計算圖像幀流的運行方差的類方法。該方法的輸入通常來自另一個數據類。我想這樣做是有每次被調用時返回一個正態分佈隨機幀進行模擬，然後有一個測試，檢查，看是否經過一些大量的幀，返回的方差爲1（內公差）。

如果我寫我的方法是這樣的：

function mock = makeMock(obj) 
     [mock, b] = createMock(obj, 'AddedMethods', {'r'}); 
     import matlab.mock.actions.AssignOutputs; 
     rng(1) 
     x = @() randn(obj.rows, obj.cols); 
     when(withAnyInputs(b.r), repeat(32, AssignOutputs(x()))); 
    end 

然後輸出分配時，randn評估和輸出是靜態的，所以我所有的幀是相同的。我試過的第二件事是要一次作爲列表中添加多個幀：

function mock = makeMock(obj) 
     [mock, b] = createMock(obj, 'AddedMethods', {'r'}); 
     import matlab.mock.actions.AssignOutputs; 
     rng(1) 
     x = num2cell(randn(obj.rows, obj.cols, 32), [1 2]); 
     when(withAnyInputs(b.r), AssignOutputs(x{:})); 
    end 

這仍然只給出第一幀，因爲AssignOutputsdeal S是其值的輸出變量，所以我總是隻請求第一個。

最後醜陋的東西我想是：

 when(withAnyInputs(b.r), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      then(AssignOutputs(randn(obj.rows, obj.cols)), ... 
      AssignOutputs(randn(obj.rows, obj.cols))) ... 
      ))))))))))))))))))))))))))))))); 

這給了我一個錯誤，說我嵌套太深。

我會注意到，我試圖測試方法，希望整個模擬對象作爲輸入，不只是框架，所以只是傳遞一個隨機幀是不可能的。這是一個非常非常大的代碼庫的一部分，因此簡單地重寫測試方法取幀直接，目前不可能沒有顯著重構一些其他的方面，所以我堅持做測試，現在這個樣子。

有一種優雅的方式做我想做的事？

Answer 1

我張貼解答了MATLAB的答案： https://www.mathworks.com/matlabcentral/answers/357200-how-can-i-make-a-mock-method-return-different-answers#answer_282110

總結：

• 有沒有乾淨的方式來做到這一點
• 然而，一個可以建立在一個操作列表環

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import matlab.mock.actions.AssignOutputs; 
[mock, b] = createMock(obj, 'AddedMethods', {'r'}); 
rng(1) 
n = 32; 
action = AssignOutputs(randn(obj.rows, obj.cols)); 
for i = 1:n-1 
    action = action.then(AssignOutputs(randn(obj.rows, obj.cols))); 
end 
when(withAnyInputs(b.r), action);