我試圖將MySQL選擇的輸出寫入變量。問題是我得到錯誤「數組到字符串轉換」。「將數組寫入字符串」同時將MySQL輸出寫入變量
$user = mysql_query("select username from user");
echo "<table border='1'>";
if (isset($_POST['winneron'])) {
echo "<tr>";
while ($printuser = mysql_fetch_array($user)) {
echo "<th align='center'>". $printuser['username'] . "</th>";
}
echo "</tr>";
$user = mysql_query("select username from user");
while ($printuser = mysql_fetch_array($user)) {
$games = mysql_query("SELECT s.spielid, date, team1, team2, sieger, wettid, u.userid, w.spielid, team
FROM user u, spiele s, wette w
WHERE u.userid = w.userid
AND u.username = '$printuser'
AND w.spielid = s.spielid"); <-- Error line
while ($printgames = mysql_fetch_array($games)) {
if ($printgames['sieger'] == $printgames['team1']) {
echo "<tr><td align='center'><b>". strtoupper($printgames['sieger']) . "</b></td></tr>";
}
else {
echo "<tr><td align='center'>". strtoupper($printgames['sieger']) . "</td></tr>";
}
}
}
}
什麼問題更換呢? – Dev
在哪一行?請注意,如果您嘗試從相同的$用戶獲取兩次,下次可能會得到一個空數組 – Fallen
編輯代碼使其更易於閱讀。 已經認爲$ user在第一次讀取後可能是空的,所以我在while循環之後再次添加了它。 – ProfGhost