訪問結果數組中的笨

Question

我有以下的情況發生在我的模型：

public function load_user_menu($username) 
    { 
     $this->db->select('*'); 
     $this->db->from('menu'); 
     $this->db->where('username', $username); 
     $query = $this->db->get(); 
     return $query->result(); 
    } 

，並在我的控制器如下：

public function index() 
    {  
     /*If user previously logged in and not logged out, username remains in session. 
      load username and load profile data. 
     */ 
     //check if user logged in or not 
     if(($this->session->userdata('username')!="")) 
     { 
      //load data from model 
      $profile = array(); 
      $username = $this->session->userdata('username'); 
      $result = $this->profileModel->user_profile($username); 
      foreach($result as &$value) 
       { 
        $profile['userdetails'] = $value; 
       } 
      $this->load->view('profile', $profile); 
     }else{ 
      //redirect to login function 
      $this->login(); 
     } 
    } 

，但我得到的曲線圖的錯誤。我相信我訪問他們錯了，因爲我做這個的觀點：

<? echo $userdetails['profilepic']; ?> 

，並沒有什麼出，但這個錯誤：

A PHP Error was encountered

Severity: Notice

Message: Trying to get property of non-object

Filename: controllers/profile.php

Line Number: 60

這是因爲錯誤的接入的肯定。我如何根據上述內容訪問細節？

Answer 1

assumming你有profilepic內的UserDetails和看到的錯誤，你試圖讓非對象的他財產，這意味着

<? echo $userdetails['profilepic']; ?> 

應該

<? echo $userdetails->profilepic; ?> 

，因爲你正在服用你造成的對象，不陣列

return $query->result(); 

，或者您更改爲

return $query->result_array(); 

Answer 2

$query->result();產生一個對象; $query->result_array();給你一個數組

要麼是好的，根據您的需要

Answer 3

只是試試這個視圖頁面

<? echo $profilepic; ?> 

Answer 4

-there上是在您的控制器不需要foreach循環作爲

$result = $this->profileModel->user_profile($username); 
      foreach($result as &$value) 
       { 
        $profile['userdetails'] = $value; 
       } 

- 試試這個。

$profile['userdetails'] = $this->profileModel->user_profile($username); 

- 要訪問的視圖，以此作爲

echo $userdetails->profilepic;