將PHP發佈到API（使用cURL嘗試）

Question

如果我直接轉到具有URL中正確參數的URL，我會收到成功響應。

的URL看起來像

https://api.theService.com/send?client_id=54&token=7545h5h554&format=json 

在PHP中，我想是這樣

error_reporting(E_ALL); 
ini_set('display_errors', 1); 

$client_id = 54; 
$token = '7545h5h554'; 

$ch = curl_init('https://api.theService.com/send?client_id='.$client_id.'&token='.$token.'&format=json'); 

// Send the request 
$response = curl_exec($ch); 

// Check for errors 
if($response === FALSE){ 
    die(curl_error($ch)); 
} 

// Decode the response 
$responseData = json_decode($response, TRUE); 

echo "<pre>"; 
echo print_r($responseData); 
echo "</pre>"; 

但是我從來沒有得到與上面的代碼的響應。

Answer 1

試試這個：

$client_id = 54; 
$token = '7545h5h554'; 
$url = "https://api.theService.com/send?client_id=$client_id&token=$token&format=json"; 

$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, $url); 
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); 
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); 
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); 
curl_setopt($ch, CURLOPT_SSLVERSION, 3); 
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10); //waits 10 seconds for response 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
$page = curl_exec($ch) or die(curl_error($ch)); 
echo $page; 

你也應該嘗試在curl_error()檢查錯誤消息。
http://www.php.net/curl_error