選擇相同的客戶名稱，但具有不同的客戶地址

Question

嘗試選擇全部爲同一客戶但地址不同的記錄。

因此，我可以稍後讓用戶選擇Bob Yonkers，然後選擇將Bob的所有記錄更新爲特定地址。所以我想顯示所有可用的記錄。

數據舉例：

 
CUSTOMER_NAME, CUSTOMER_ADDRESS 
Bob Yonkers , 42 Satellite Cir 
Bob Yonkers , 667 Orbit St 
Bob Yonkers , 42 Satellite Cir 
Bob Yonkers , 667 Orbit St 
David Boom , 5959 Bush Ave 
David Boom , 5959 Bush Ave 
David Boom , 5959 Bush Ave 
David Boom , 5959 Bush Ave 
David Boom , 5959 Bush Ave 
Ruby Tuesday , 123 Highway Ln Apt#1 
Ruby Tuesday , 123 Highway Ln 
David Boom ,5959 Bush Ave 
David Boom ,5959 Bush Ave 
David Boom ,5959 Bush Ave 

所以查詢將帶回這些結果...

結果舉例：

 
CUSTOMER_NAME, CUSTOMER_ADDRESS 
Bob Yonkers , 42 Satellite Cir 
Bob Yonkers , 667 Orbit St 
Ruby Tuesday , 123 Highway Ln Apt#1 
Ruby Tuesday , 123 Highway Ln 

任何幫助，將不勝感激。

Answer 1

這是喬爾的改進：

SELECT distinct t1.* 
FROM [table] t1 
INNER JOIN [table] t2 ON t1.Name=t2.Name AND t1.Address<>t2.Address 

Answer 2

SELECT * 
FROM [table] t1 
INNER JOIN [table] t2 ON t1.Name=t2.Name AND t1.Address<>t2.Address 

Answer 3

試試這個...

select * from (select count(customername) as ct, customername, address from table group by customername, address) t1 
where t1.ct>1 

Answer 4

這吸引了我，因爲一個朋友問我類似的東西。下面的查詢將解決這個問題，儘管在-有效：

mysql> select DISTINCT CUSTOMER_NAME,CUSTOMER_ADDRESS from CUST_ADDR where CUSTOMER_NAME in (select CUSTOMER_NAME from CUST_ADDR GROUP BY CUSTOMER_NAME HAVING COUNT(DISTINCT CUSTOMER_ADDRESS) > 1);

+---------------+----------------------+ 
| CUSTOMER_NAME | CUSTOMER_ADDRESS  | 
+---------------+----------------------+ 
| Bob Yonkers | 42 Satellite Cir  | 
| Bob Yonkers | 667 Orbit St   | 
| Ruby Tuesday | 123 Highway Ln Apt#1 | 
| Ruby Tuesday | 123 Highway Ln  | 
+---------------+----------------------+ 
4 rows in set (0.01 sec)