-3
arr1 = [
{Lattitude: '52,4043000', Location: 'a2', Longitude: '55,7181815'},
{Lattitude: '52,3882320', Location: 'b2', Longitude: '55,7225500'},
{Lattitude: '52,4041184', Location: 'c2', Longitude: '55,7172296'},
{Lattitude: '52,3996194', Location: 'd2', Longitude: '55,7200249'},
];
arr2 = [
{Lattitude: '52,3882320', Location: 'b2', Longitude: '55,7225500'},
{Lattitude: '52,4041184', Location: 'c2', Longitude: '55,7172296'},
{Lattitude: '52,3996194', Location: 'd2', Longitude: '55,7200249'}
];
如何,我可以比較兩個JSON陣列ARR1,ARR2的得到的只是這個元素從ARR1 {Lattitude: '52,4043000', Location: 'a2', Longitude: '55,7181815'}
它沒有在ARR2如何採取元素從兩個JSON數組中的jQuery
我心底嘗試做像這
function objDiff(arr1, arr2) {
var resultArray = [];
for (var i = 0; i < arr1.length; i++) {
for (var j = 0; arr2.length; j++) {
if (parseFloat(parseFloat(arr1[i].Lattitude).toFixed(4)) != parseFloat(parseFloat(arr2[i].Lattitude).toFixed(4)) &&
parseFloat(parseFloat(arr1[i].Longitude).toFixed(4)) != parseFloat(parseFloat(arr2[i].Longitude).toFixed(4))) {
resultArray.push(arr1[i]);
}
}
}
return resultArray;
}
,但我沒有功能的作品,我不`噸知道爲什麼
如果交換變量的內容,這可能不起作用。不知道OP如何成爲它!編輯後的 – Rayon
也適用於變量交換。 – San
該代碼將比循環執行速度快10倍。 – San