合併所有以IF開始並以分號結尾的行

Question

我陷入了下面的問題。我用while循環完成了這個工作，並且它工作正常，但無法省略每個循環中附加字符串的序列號。

我有一個文件內容

1 SELECT abc from a ; 

    2 .IF activi <> 1 
    3 THEN 
    4 QUIT; 
    5 .IF ERROR <> 0 THEN QUIT ERROR; 
    6 SELECT 
    7 a, 
    8 b, 
    9 c 
    10 FROM xyz; 
    11 .IF ERROR <> 0 
    12 THEN 
    13 QUIT ERROR; 

我想在同一個文件 編輯與下面的輸出

1 SELECT abc from a;  
    2 .IF activi <> 1 THEN QUIT ; 
    5 .IF ERROR <> 0 THEN QUIT ERROR; 
    6 SELECT 
    7 a, 
    8 b, 
    9 c 
    10 FROM xyz;  
    11 .IF ERROR <> 0 THEN QUIT ERROR; 

Answer 1

隨着SED：

$ sed '/\.IF/{:a;/; *$/!{N;s/ *\n *[0-9]*//;ta}}' file 

輸出：

1 SELECT abc from a ; 

    2 .IF activi <> 1 THEN QUIT; 
    5 .IF ERROR <> 0 THEN QUIT ERROR; 
    6 SELECT 
    7 a, 
    8 b, 
    9 c 
    10 FROM xyz; 
    11 .IF ERROR <> 0 THEN QUIT ERROR; 

說明：

sed ' 
/\.IF/ {     # for lines containing ".IF" 
    :a;     # define a "a" label for upcoming loop 
    /; *$/! {    # if line does not contain ";" 
     N;     # add next line to pattern space 
     s/ *\n *[0-9]*//; # remove newline and leading digits 
     ta;    # loops to label "a" if ";" is not found 
    } 
}' file