SyntaxError：意外的標記'='。在參數聲明後需要''''或''''。'在safari

我混淆了一些JS代碼，它似乎在firefox中工作（沒有錯誤和功能正確），但拋出'SyntaxError：意外的標記'='。在參數聲明後需要''''或''''。'在safari中。我在PHP中的下列對象SyntaxError：意外的標記'='。在參數聲明後需要''''或''''。'在safari

$items = Array ([0] => stdClass Object ([id] => 1 [class] => class_a [make] => Kia [model] => Picanto [features] => 3,4,5,6,7,8 [colour] => white [engine] => 1000cc [ordering] => 1 [published] => 1 [image] => images/vehicles/picanto.jpg) [1] => stdClass Object ([id] => 2 [class] => motorbike [make] => Honda [model] => Transalp [features] => [colour] => blue [engine] => 650cc [ordering] => 6 [published] => 1 [image] =>) [2] => stdClass Object ([id] => 3 [class] => moped [make] => Sym [model] => SR [features] => [colour] => white [engine] => 150cc [ordering] => 5 [published] => 1 [image] =>) [3] => stdClass Object ([id] => 4 [class] => class_b [make] => Suzuki [model] => Splash [features] => 12 [colour] => Red [engine] => 1300cc [ordering] => 3 [published] => 1 [image] => images/vehicles/suzuki_splash.jpg) [4] => stdClass Object ([id] => 5 [class] => class_f [make] => Peugot [model] => 307 Cabrio [features] => 8,9,10,11 [colour] => Black [engine] => 1600cc [ordering] => 4 [published] => 1 [image] => images/vehicles/peugeot307.jpg) [5] => stdClass Object ([id] => 6 [class] => class_a [make] => Hyundai [model] => Atos [features] => [colour] => white [engine] => 1100cc [ordering] => 2 [published] => 1 [image] => images/vehicles/atos.jpg))

並在瀏覽器中json_encode行如下

var items = [{"id":"1","class":"class_a","make":"Kia","model":"Picanto","features":"3,4,5,6,7,8","colour":"white","engine":"1000cc","ordering":"1","published":"1","image":"images\/vehicles\/picanto.jpg"},{"id":"2","class":"motorbike","make":"Honda","model":"Transalp","features":"","colour":"blue","engine":"650cc","ordering":"6","published":"1","image":""},{"id":"3","class":"moped","make":"Sym","model":"SR","features":"","colour":"white","engine":"150cc","ordering":"5","published":"1","image":""},{"id":"4","class":"class_b","make":"Suzuki","model":"Splash","features":"12","colour":"Red","engine":"1300cc","ordering":"3","published":"1","image":"images\/vehicles\/suzuki_splash.jpg"},{"id":"5","class":"class_f","make":"Peugot","model":"307 Cabrio","features":"8,9,10,11","colour":"Black","engine":"1600cc","ordering":"4","published":"1","image":"images\/vehicles\/peugeot307.jpg"},{"id":"6","class":"class_a","make":"Hyundai","model":"Atos","features":"","colour":"white","engine":"1100cc","ordering":"2","published":"1","image":"images\/vehicles\/atos.jpg"}];

它看起來正確的，所以我不把下面的JavaScript

<script type="text/javascript"> 
jQuery(document).ready(function($){ 
    var items = <?PHP echo json_encode($items)?>; 
    console.log(items); 
    for (var i = 0, len = items.length; i < len; i++) { 
     lookup[items[i].id] = items[i];  //access the new lookup object using lookup[id].variable i.e lookup[1].image 
    } 
    var vId =""; 
    function updateImg(img, display=true){ 
     if (display == true){ 
      $("#vehicle-image").show(500); 
     }else{ 
      $("#vehicle-image").hide(500); 
     } 

     $("#vehicle-image").attr("src", '/'+ img); 

    } 
    $('#jform_vehicle').on('change', function() { 
     var vId = parseInt(($("#jform_vehicle").chosen().val())); 
     console.log (vId); 
     if (isNaN(vId) !==true){ 
      var img = lookup[vId].image; 
      console.log ('img=' + img); 
      updateImg(img); 
     }else{ 
      console.log('not a number'); 
      var img = ""; 
      updateImg(img, false) 
     } 
    }); 
}); 
</script>

知道是什麼導致了錯誤。有任何想法嗎？乾杯。

Safari瀏覽器指向這裏的錯誤代碼 safari error

來源

2016-05-23 philip

分享錯誤來臨的代碼 – C2486

格式化您的問題時請格外小心。我試圖爲你格式化PHP代碼，雖然它不是接近於語法正確的事件，因爲我假設你已經從某種記錄器中複製它。 –

我點擊發送它認爲它會預覽代碼。我的錯誤和值得的負分數！從代碼中可以看出，我是一個完全新手。 – philip

如果你有這樣的功能，從

function abc(a=2){ 
}

更改這些喜歡這個

function abc(a){ 
    if(a === undefined){ 
    a = 2; 
    } 
}

Safari瀏覽器不允許轉讓像這樣的功能，在上面的第一個。

來源

2016-05-23 15:39:40 C2486

嘿Rishi，發現的榮譽。太感謝了。惱人的是，safari中的錯誤控制檯（如我編輯的原始文章所示）指向json_encode行。我不知道我是否可以，但會嘗試更新標題，以便幫助其他人。 – philip

現在你已經告訴了我錯誤是什麼，有很多這方面的話題。在我的防守中，Safari控制檯沒有指出錯誤的正確代碼區域。將其重命名爲safar錯誤消息，以便它可以幫助其他人 – philip

感謝100萬！一切工作正常，直到我在iPhone上嘗試... +！ –

SyntaxError：意外的標記'='。在參數聲明後需要''''或''''。'在safari

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