PHP獲得之日起一個月後

Question

<?php 

echo "\n"; 
echo $end_date = date('Y-m-d', strtotime('+1 month')); 
echo "\n"; 
$today = date("Y-m-d"); // 2012-01-30 
echo $next_month = date("Y-m-d", strtotime("$today +1 month")); 
echo "\n"; 
$end_date = mktime(date("H"), date("i"), date("s"), date("n") + 1, date("j"), date("Y")); 
echo "\n" . date('Y-m-d',$end_date); 

http://codepad.org/bHiNFIBR

我怎樣才能得到正確的日期1個月 我嘗試了這些選項。 都回到5月1日，但我需要4月30日

Answer 1

試着這麼做那..

if(date('d') == 31 || (date('m') == 1 && date('d') > 28)){ 
    $date = strtotime('last day of next month'); 
} else { 
    $date = strtotime('+1 months'); 
} 

echo date('Y-m-d', $date); 

但只要注意，當你3月31日爲1個月+其正確的目標5月1日並非4月30日:)

Answer 2

我建議這樣的：

$next_month = date('Y-m-d', strtotime("+1 months", strtotime("NOW"))); 

編輯

function addMonth($date) { 
    $date = new DateTime($date); 
    $day = $date->format('j'); 

    $date->modify("+1 month"); 
    $next_month_day = $date->format('j'); 

    if ($day != $next_month_day) 
     $date->modify('last day of last month'); 

    return $date; 
} 

$next_month = addMonth(time()); 
echo $next_month->format("Y-m-d"); 

希望這有助於:-)

Answer 3

嘗試這種解決方案：

echo "\n"; 
$today = date("Y-m-d"); 
$next_month = date("Y-m-d", strtotime("$today +1 month")); 
echo "\n"; 
echo $next_month_last_day = date("Y-m-d",strtotime('-1 second',strtotime($next_month)));