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即時爲網站做一個快速更新,但xslt不是我的東西,它似乎與代碼我看代碼生成的代碼失敗 - 已包括兩個以下:xml xsl template with html/js內部失敗
當前代碼:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxml="urn:schemas-microsoft-com:xslt"
xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib"
exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib ">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:param name="currentPage"/>
<xsl:template match="/">
<xsl:if test="string-length($currentPage/mp4videoLinkId) > 0">
<xsl:variable name="videoID" select="$currentPage/mp4videoLinkId" />
<xsl:variable name="srtID" select="$currentPage/mp4videoSRTId" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script src="flowplayer-3.2.6.min.js"></script>
<script src="flowplayer.ipad-3.2.2.min.js"></script>
<!-- player container-->
<a href="{$videoID}" style="display:block;width:473px;height:310px;" id="ipad"></a>
<script type="text/javascript">
$f("ipad", "flowplayer-3.2.7.swf",{
clip: {
autoPlay: false,
url: '{$videoID}',
// this is the Timed Text file with captions info
captionUrl: '{$srtID}'
},
plugins: {
captions: {
url: 'flowplayer.captions-3.2.3.swf',
// pointer to a content plugin (see below)
captionTarget: 'content'
},
// configure a content plugin to look good for our purpose
content: {
url:'flowplayer.content-3.2.0.swf',
bottom: 25,
width: '80%',
height:40,
backgroundColor: 'transparent',
backgroundGradient: 'none',
borderRadius: 4,
border: 0,
textDecoration: 'outline',
style: {
body: {
fontSize: 14,
fontFamily: 'Arial',
textAlign: 'center',
color: '#ffffff'
}
}
}
}
}).ipad();
</script>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
產生源: (你可以看到它打破了代碼,而不是關閉,然後顯示{$標籤})我失去了什麼?
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" /><script src="flowplayer-3.2.6.min.js" /><script src="flowplayer.ipad-3.2.2.min.js" /><a href="mp4/assist-mi-car-parking.mp4" style="display:block;width:473px;height:310px;" id="ipad" /><script type="text/javascript">
$f("ipad", "flowplayer-3.2.7.swf",{
clip: {
autoPlay: false,
url: '{$videoID}',
// this is the Timed Text file with captions info
captionUrl: '{$srtID}'
},
plugins: {
captions: {
url: 'flowplayer.captions-3.2.3.swf',
// pointer to a content plugin (see below)
captionTarget: 'content'
},
// configure a content plugin to look good for our purpose
content: {
url:'flowplayer.content-3.2.0.swf',
bottom: 25,
width: '80%',
height:40,
backgroundColor: 'transparent',
backgroundGradient: 'none',
borderRadius: 4,
border: 0,
textDecoration: 'outline',
style: {
body: {
fontSize: 14,
fontFamily: 'Arial',
textAlign: 'center',
color: '#ffffff'
}
}
}
}
}).ipad();
</script>
很大,那現在顯示的數據!然而,它仍然只包括jquery,沒有看到螢火蟲之後,在源代碼中,它不關閉,我認爲這可以防止休息顯示..... – 2012-02-27 17:10:27
@JamesBrandon:您的XSLT轉換可能有其他錯誤 - 你需要展示一個完整的(儘可能小的以便重現問題)XML文檔,一個完整的(儘可能小但重現問題)XSLT轉換,你得到的完整結果,你想要的完整結果*獲得以及該轉換必須實施的任何規則。至於這個問題,已經完全回答了。請爲其他問題提出一個新問題,並提供所有必要的信息來重現這個新問題。 – 2012-02-27 17:16:06