1
我有一張表格,名爲學生,我在表單中顯示可以更新他們的數據。在表格中顯示數據用於更新目的
我也有一個名爲Groepen(組)的表,有些學生是一個組的一部分。他們所屬的小組也被顯示出來。並且有一個選擇讓學生成爲一個組的一部分。
如果學生一組的一部分,我更新的情況下,他的電話號碼,他是不是該組中再更新後。
我該如何預防?
我的代碼是
<?php
$q = "SELECT * FROM students LEFT JOIN Groepen ON Groepen.groep_id=students.groep WHERE students.uid = '$user[uid]' ORDER BY st_last ASC";
$r = mysqli_query($dbc, $q);
if (mysqli_num_rows($r) > 0) {
echo "
<p>Om gegevens te wijzigen of aan te vullen kunt u gewoon in het desbetreffende veld typen en vervolgens op 'update' klikken.</p></br></br>
<table class='table'>
<thead>
<tr>
<th>Naam</th>
<th>Voornaam</th>
<th>Graad</th>
<th>Telefoon</th>
<th>Gsm</th>
<th>Email</th>
<th>Lid van groep</th>
<th>Toevoegen aan/verwijderen uit groep</th>
</tr>
</thead>";
while($student_list = mysqli_fetch_assoc($r)) { ?>
<tbody>
<form action="" method="POST" role="form">
<tr>
<input type="hidden" value="<?php echo $student_list['sid']?>" name="sid" />
<td width="8%"><input type="text" class="form-control" name="st_last" value="<?php echo $student_list['st_last']; ?>" /></td>
<td width="6%"><input type="text" class="form-control" name="st_first" value="<?php echo $student_list['st_first']; ?>"/></td>
<td width="2%"><input type="text" class="form-control" name="graad" value="<?php echo $student_list['graad']; ?>"/></td>
<td width="7%"><input type="text" class="form-control" name="vaste_telefoon" value="<?php echo $student_list['vaste_telefoon']; ?>"/></td>
<td width="7%"><input type="text" class="form-control" name="gsm" value="<?php echo $student_list['gsm']; ?>"/></td>
<td width="10%"><input type="text" class="form-control" name="email" value="<?php echo $student_list['email']; ?>"/></td>
<td width="8%" style="padding-top: 15px;"><?php echo $student_list['groepsnaam']; ?></td>
<td width="7%"><div class="form-group">
<select class="form-control" name="groep_id" id="groep">
<option value="><?$student_list['groepid']; ?>"><?php echo $student_list['groepsnaam']; ?></option>
<?php
$q2 = "SELECT * FROM Groepen ORDER BY groepsnaam ASC";
$r2 = mysqli_query($dbc, $q2);
while($groep_list = mysqli_fetch_assoc($r2)) {
?>
<option value="<?php echo $groep_list['groep_id']; ?>"><?php echo $groep_list['groepsnaam']; ?></option>
<?php } ?>
</select>
</div></td>
<td width="12%"> <div class="btn-group" role="group" aria-label="...">
<button type="submit" name="updatell" class="btn btn-warning">Update</button>
<button type="submit" name="deletell" class="btn btn-danger">Delete</button></td>
</tr>
</form>
</tbody>
<?php } }
else {
echo "U hebt nog geen leerlingen toegevoegd.";
}
?>
</table>
而且更新查詢:
<?php
if(isset($_POST['updatell'])) {
$qupdatestudent = "UPDATE students SET st_last='$_POST[st_last]', st_first='$_POST[st_first]', groep='$_POST[groep_id]', graad='$_POST[graad]', vaste_telefoon='$_POST[vaste_telefoon]', gsm='$_POST[gsm]', email='$_POST[email]' WHERE sid='$_POST[sid]'";
$r2 = mysqli_query($dbc, $qupdatestudent);
}
if(isset($_POST['deletell'])) {
$deletestudent = "DELETE FROM students WHERE sid='$_POST[sid]'";
$r3 = mysqli_query($dbc, $deletestudent);
}
?>
非常感謝!作品。不知道選擇='選擇'的解決方案。 –
@BertLietaert很高興我能幫到你。如果解決了您的問題,請*接受*答案。 [如何接受Stack Overflow的答案?](http://meta.stackexchange.com/a/5235) –