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在開始閱讀之前,如果以下解釋太長,並且您不會閱讀下面的代碼。如何循環訪問SQL Server數據透視查詢
請你可以覆蓋它,只看最後一行。
我有這個正常循環查詢使用光標,它的效果很好。
DECLARE db_cursor CURSOR FOR
Select top 100 percent
[students].stu_id as StuID, Major_ID,MajorSeq,
SysDate, Points
From
[dbo].[StudentRegsterations]
inner join
[dbo].[students] on [dbo].[StudentRegsterations].Stu_ID = [dbo].[students].stu_id
order by
[Points] desc, [SysDate] desc;
DECLARE @StuID [int];
DECLARE @Major_ID [int];
DECLARE @MajorSeq [int];
DECLARE @SysDate [date];
DECLARE @Points [decimal](10, 2);
OPEN db_cursor;
FETCH NEXT FROM db_cursor INTO @StuID, @Major_ID, @MajorSeq, @SysDate, @Points;
WHILE @@FETCH_STATUS = 0
BEGIN
--Do stuff with scalar values
--InsertThisStudent()
print CAST(@Points as varchar(10)) + ' - ' + CAST(@SysDate as varchar(20))
FETCH NEXT FROM db_cursor INTO @StuID, @Major_ID, @MajorSeq, @SysDate, @Points;
END;
CLOSE db_cursor;
DEALLOCATE db_cursor;
上面的查詢循環拋出正常選擇。
但是,如果我改變它爲樞軸查詢給了我下面的錯誤。
消息16924,級別16,狀態1,行31
Cursorfetch:在INTO列表必須與所選列的聲明的變量數目。
和導致錯誤的數據透視查詢是這樣的。
DECLARE db_cursor CURSOR FOR
SELECT *
FROM
(Select top 100 percent
[students].stu_id as StuID, SysDate, Points, MajorSeq, Major_ID
From
[dbo].[StudentRegsterations]
inner join
[dbo].[students] on [dbo].[StudentRegsterations].Stu_ID = [dbo].[students].stu_id) WorkOrders
PIVOT
(
max(Major_ID)
FOR [MajorSeq] IN (
[1],[2],[3],[4],[5],[6],[7],[8],[9],[10],
[11],[12],[13],[14],[15],[16],[17],[18],[19],[20]
)
) AS PivotTable
order by [Points] desc,[SysDate] desc
DECLARE @StuID [int];
DECLARE @Major_ID [int];
DECLARE @MajorSeq [int];
DECLARE @SysDate [date];
DECLARE @Points [decimal](10, 2);
DECLARE @1 [int];DECLARE @2 [int];DECLARE @3 [int];DECLARE @4 [int];DECLARE @5 [int];DECLARE @6 [int];DECLARE @7 [int];
DECLARE @8 [int];DECLARE @9 [int];DECLARE @10 [int];DECLARE @11 [int];DECLARE @12 [int];DECLARE @13 [int];DECLARE @14 [int];
DECLARE @15 [int];DECLARE @16 [int];DECLARE @17 [int];DECLARE @18 [int];DECLARE @19 [int];DECLARE @20 [int];
OPEN db_cursor;
FETCH NEXT FROM db_cursor INTO @StuID, @Major_ID, @MajorSeq, @SysDate, @Points,
@1,@2,@3,@4,@5,@6,@7,@8,@9,@10,@11,@12,@13,@14,@15,@16,@17,@18,@19,@20;
WHILE @@FETCH_STATUS = 0
BEGIN
--Do stuff with scalar values
--InsertThisStudent()
print CAST(@Points as varchar(10)) + ' - ' + CAST(@SysDate as varchar(20))
FETCH NEXT FROM db_cursor INTO @StuID, @Major_ID, @MajorSeq, @SysDate, @Points, @1,@2,@3,@4,@5,@6,@7,@8,@9,@10,@11,@12,@13,@14,@15,@16,@17,@18,@19,@20;
END;
CLOSE db_cursor;
DEALLOCATE db_cursor;
簡單地說所有我想要的東西,使用任何的SQL Server的方式,通過轉動查詢循環,使用任何小的查詢樣品,未提交我的代碼。
你對我的代碼沒有本質錯誤,如你所說。我不會從樞軸選擇中出現兩列('@Major_ID,@ MajorSeq')。因爲他們填充了樞軸列'@ 1,@ 2,@ 3,'....等一旦我刪除它查詢得到正確工作。 –