如何轉換INT（輸入）到列表

Question

從這個評論：

I mean if the user inputs "00000000" which is an integer, it will become [0,0,0,0,0,0,0,0]

我相信所有你想要的是：

a = list(map(int, input("enter first byte: "))) 
b = list(map(int, input("enter second byte: "))) 

編輯：python3兼容性變化得益於Tadhg麥當勞 - 延森

EDIT2：既然你不能在列表使用^，你也可以使用此代碼：

a = input("enter first byte: ") 
b = input("enter second byte: ") 

def half_adder(a, b): 
    S = "" 
    c = "" 
    for i in range(8): 
     S += str(int(a[i])^int(b[i])) 
     c += str(int(a[i]) & int(b[i])) 
    return (S,c) 

def full_adder(a, b, c): 
    (s1, c1) = half_adder(a, b) 
    (s2, c2) = half_adder(s1, c) 
    return (s2, (c1 or c2)) 

print(full_adder(a, b, "00000000")) 

Answer 1

我覺得這是你所需要的：

>>> x=42 
>>> list(map(int, "{:08b}".format(x))) 
[0, 0, 1, 0, 1, 0, 1, 0] 

格式字符串"{:08b}"意味着：整數轉換爲字符串以二進制，至少8位，0填充。

Answer 2

從這個評論：

I mean if the user inputs "00000000" which is an integer, it will become [0,0,0,0,0,0,0,0]

我相信所有你想要的是：

a = list(map(int, input("enter first byte: "))) 
b = list(map(int, input("enter second byte: "))) 

編輯：python3兼容性變化得益於Tadhg麥當勞 - 延森

EDIT2：既然你可以」在列表上使用^，您可以改爲使用此代碼：

a = input("enter first byte: ") 
b = input("enter second byte: ") 

def half_adder(a, b): 
    S = "" 
    c = "" 
    for i in range(8): 
     S += str(int(a[i])^int(b[i])) 
     c += str(int(a[i]) & int(b[i])) 
    return (S,c) 

def full_adder(a, b, c): 
    (s1, c1) = half_adder(a, b) 
    (s2, c2) = half_adder(s1, c) 
    return (s2, (c1 or c2)) 

print(full_adder(a, b, "00000000"))