Question

我知道有些帖子幾乎與我通過其中很多人看過的內容幾乎相同，但可悲的是還沒有找到解決方案。我的問題是我寫了一個電子郵件valiadtor使用jQuery的.addmethod（）函數jQuery驗證插件。

$.validator.addMethod("uniqueEmail", function(value, element) { 
    $.ajax({ 
     data: 'email=' + value, 
     type: 'get', 
     url: 'functions/emailcheck.php', 
      dataType:"html", 
      success: function(msg) { 
       alert("M:"+msg+" V:"+value); 
       if(msg == true || msg != null || msg == "true"){ 
        return true; 
        alert("TRUE!!!"); 
       } 
       else{ 
        return false; 
       } 
      } 
     }); 
    }); 

在驗證規則

則...

email: { required: true, email: true, uniqueEmail: true }, 

後來終於即使在這個PHP文件....

<?php 
    echo "true"; 
?> 

它給我的警告，真實已是註冊，郵件中有郵件.. uniqueEmail: jQuery.format("{0} has already been registered")。現在我有一個調試警報設置int他ajax調用。它顯示它返回true，並且該值與輸入一樣。

我希望有一些幫助，這會讓我瘋狂，我有一種感覺，這對你們中的一些人來說是顯而易見的！

PS 我的繼承人充分驗證減去上述附加的方法...

$(".form_registration_submit").click(function() { 
     $(".qtip").remove(); 
     $("#form_registration").validate({ 
      onfocusout: function(element){ 
       $(".qtip").remove(); 
      }, 
      rules: { 
       name: { 
        required: true, 
        minlength: 3 
       }, 
       firstname: { 
        required: true, 
        minlength: 3 
       }, 
       lastname: { 
        required: true, 
        minlength: 3 
       }, 
       username: { 
        required: true, 
        minlength: 3 
       }, 
       password: { 
        required: true, 
        minlength: 5 
       }, 
       confirm_password: { 
        required: true, 
        minlength: 5, 
        equalTo: "#form_registration_password" 
       }, 
       email: { 
        required: true, 
        email: true, 
        uniqueEmail: true 
       }, 
       topic: { 
        required: "#newsletter:checked", 
        minlength: 2 
       }, 
       agree: "required" 
      }, 
      messages: { 
       name: "Please enter your name", 
       firstname: "Please enter your firstname", 
       lastname: "Please enter your lastname", 
       username: { 
        required: "Please enter a username", 
        minlength: "Your username must consist of at least 2 characters" 
       }, 
       password: { 
        required: "Please provide a password", 
        minlength: "Your password must be at least 5 characters long" 
       }, 
       confirm_password: { 
        required: "Please confirm your password", 
        minlength: "Your password must be at least 5 characters long", 
        equalTo: "Please enter the same password as above" 
       }, 
       email: { 
        required: "Please enter a valid email address", 
        uniqueEmail: jQuery.format("{0} has already been registered") 
       }, 
       agree: "Please accept our policy" 
      }, 
      errorPlacement: function(error, element) { 
       element.qtip(
        { 
         show: { solo: false, ready: true, delay: 0 }, 
         hide: { when:false }, 
         content: eval(error), 
         style: { name: 'dark', border: { width: 1, radius: 1, color:"red" }, tip: 'bottomLeft' }, 
         position: { 
          corner: { target: 'topRight', tooltip: 'bottomLeft' }, 
          adjust: { x: 0 , y: 0 } 
         } 
        }); 
      }, 
      submitHandler: function(form) { 
       $(".qtip").remove(); 
       jQuery(form).ajaxSubmit({ 
        target: "#login_result" 
       }); 
      } 
     }); 
    }); 

Answer 1

您的驗證函數實際上並沒有返回任何值，因此評估爲false。默認情況下，.ajax()請求是異步的，這意味着驗證功能在有機會執行成功回調之前結束。

這個問題的.post inside jQuery.validator.addMethod always returns false

Answer 2

也許您的驗證碼是點擊功能（或其他事件）裏面，所以它被稱爲多少次？ 你應該把它放在$（document）.ready（）裏面。 此外，你應該發送的數據，因爲這：

... 
data: {'email': value}, 
... 

因此它將url編碼。如果你不這樣做，電子郵件，如'a@a.c&om'將是有效的

Answer 3

重複只需添加異步：false參數爲您的Ajax調用，你會好起來