解析錯誤：語法錯誤，意外的'$ password'（T_VARIABLE）

Question

我檢查了一切。它仍然沒有工作，當我把分號（;）在第6行它說

Parse error: syntax error, unexpected ';' in line 6 

我該怎麼辦？這裏是我的代碼：

<?php 

if(isset($_POST['logintoadminpanel'])) 
( 

    include_once 'connection.php'; 

    $username = $_POST['username']; 
    $password = $_POST['password']; 


    if(empty($username) || empty($password)) 
    (
     echo "Please fill the required fields"; 
    ) 
) 
?> 

Answer 1

您正在使用parens塊。你需要使用大括號。

if (...) 
{ 
    ... 
} 

Answer 2

使用{}代替（）for if條件。

<?php 

if(isset($_POST['logintoadminpanel'])) 
{ 

    include_once 'connection.php'; 

    $username = $_POST['username']; 
    $password = $_POST['password']; 


    if(empty($username) || empty($password)) 
    { 
     echo "Please fill the required fields"; 
    } 
} 
?> 

Answer 3

Please check below tested code.. 

<?php 

if(isset($_POST['logintoadminpanel'])) 
{ 

    include_once ('connection.php'); 

    $username = $_POST['username']; 
    $password = $_POST['password']; 


    if(empty($username) || empty($password)) 
    { 
     echo "Please fill the required fields"; 
    } 
} 
?>