2
任何人都可以將此查詢轉換爲活動記錄codeigniter?codeigniter中的有效記錄
SELECT b.name,
SUM(CASE WHEN c.size = 'S' THEN 1 ELSE 0 END) S,
SUM(CASE WHEN c.size = 'M' THEN 1 ELSE 0 END) M,
SUM(CASE WHEN c.size = 'L' THEN 1 ELSE 0 END) L,
SUM(CASE WHEN c.size = 'XL' THEN 1 ELSE 0 END) XL
FROM orderTB a
INNER JOIN productTB b
ON a.id_product = b.id_shirt
INNER JOIN sizeTB c
ON a.id_size = c.id_size
GROUP BY b.name
我已經試過這樣
function get()
{
$this->db->select("b.name,SUM(CASE WHEN c.size ='S' THEN 1 ELSE 0 END) as S,SUM(CASE WHEN c.size = 'M' THEN 1 ELSE 0 END) as M,SUM(CASE WHEN c.size = 'L' THEN 1 ELSE 0 END) as L,SUM(CASE WHEN c.size = 'XL' THEN 1 ELSE 0 END) as XL");
$this->db->from('order');
$this->db->join('ukuran','order.id_size=ukuran.id_size');
$this->db->where('date',$date);
return $this->db->get();
}
,但其錯誤
不該你更願意選擇'b.name,c.size,COUNT(*)FROM ... GROUP BY b.name,c.size',然後重新組織數據? – 2013-01-01 11:42:51
將FALSE添加爲您的第二個參數 –