替代蟒蛇代替

Question

我想知道是否有下面的代碼的選擇，因爲，1：有錯誤，和2：我不想做不斷：

restring=string.replace("a","01").replace("b","02")... 

守則可能取代：

chars=["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","t","s","u","v","w","x","y","z"] 
numbs=["01","02","03","04","05","06","07","08","09","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26"] 
string="test"; 
restring=string.replace(chars,numbs); 
print restring; 

Answer 1

這裏，因爲你只有1個字符替換 「鑰匙」，我會用字典和join：

>>> chars=["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","t","s","u","v","w","x","y","z"] 
>>> numbs=["01","02","03","04","05","06","07","08","09","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26"] 
>>> d = dict(zip(chars,numbs)) 
>>> my_sentence = "foobar" 
>>> ''.join(d.get(c,c) for c in my_sentence) 
'061515020118' 

雖然不會縮放到多個字符替換鍵...