1
我無法檢索我的地址簿的姓氏。我只想通過字母表中的每個字母來檢索姓氏。Xcode,只檢索地址簿姓氏與字母A(等等)
這是我的代碼至今
ABAddressBookRef addressBook = ABAddressBookCreate();
totalPeople = (__bridge_transfer NSMutableArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
NSString *aString = @"A";
for(int i =0;i<[totalPeople count];i++){
ABRecordRef thisPerson = (__bridge ABRecordRef)
[totalPeople objectAtIndex:i];
lastName = (__bridge_transfer NSString *) ABRecordCopyValue(thisPerson, kABPersonLastNameProperty);
}
我不知道以後該怎麼辦,謝謝你看這個。
現在就是這個樣子
ABAddressBookRef addressBook = ABAddressBookCreate();
totalPeople = (__bridge_transfer NSMutableArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);
NSString *aString = @"A";
for(int i =0;i<[totalPeople count];i++){
ABRecordRef thisPerson = (__bridge ABRecordRef)
[totalPeople objectAtIndex:i];
lastName = (__bridge_transfer NSString *) ABRecordCopyValue(thisPerson, kABPersonLastNameProperty);
NSString *firstLetterOfCopiedName = [lastName substringWithRange: NSMakeRange(0,1)];
if ([firstLetterOfCopiedName compare: aString options: NSCaseInsensitiveSearch] == NSOrderedSame) {
//This person's last name matches the string aString
aArray = [[NSArray alloc]initWithObjects:lastName, nil];
}
}
它onlys增加了一個名字到陣列中,我應該怎麼才能做補充說明了一切。 對不起,我是相當新的ios開發!
非常感謝你,我更新了代碼。你能再看一遍,請告訴我我做錯了什麼。 – 2012-04-19 03:09:17
已更新我的回答 – danielbeard 2012-04-19 03:28:45
哇這個作品,非常感謝你幫助我! – 2012-04-19 03:38:42