如何從與條件

Question

兩個表的選擇有兩個表：

表1：

id = 0  name=JOHN   speciality =dentist 
id = 1  name=ABY   speciality= dentist 
id = 2  name = SARA   speciality= cardiologist 

，...
表2：

id = 0 name = JOHN   city=paris 
id = 1 name = ABY   city=tokio 
id = 1 name = SARA   city=london 

$city='pa'; 

$speciality='dentist'; 

（這兩個變量來自用戶已經進入的搜索表單）

我想要sa y這：

select * FROM Table 1 WHERE speciality=$speciality AND city LIKE %$city% (from Table2) ; 

我該說什麼？ （很明顯，ID是兩個表的每一行相同，每個ID都代表一個人）

Answer 1

嘗試這樣的：

select t1.* FROM Table 1 as t1,table2 as t2 WHERE t1.speciality='$speciality' AND t1.city LIKE %$city% and t1.name=t2.name; 

如果行ID是相同的兩個表，則：

select t1.* FROM Table 1 as t1,table2 as t2 WHERE t1.speciality='$speciality' AND t1.city LIKE %$city% and t1.name=t2.name and t1.id=t2.id ;