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我的應用程序有一個RSS tableView和另一個WebView的頁面。我可以打開的WebView用任何物體在RSS的點擊,但我無法通過鏈接並在web視圖顯示網站 下面是我的代碼RSS鏈接將在WebView(iOS)中打開
(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
int storyIndex = [indexPath indexAtPosition: [indexPath length] - 1];
NSString * storyLink = [[stories objectAtIndex: storyIndex] objectForKey: @"link"];
// clean up the link - get rid of spaces, returns, and tabs...
storyLink = [storyLink stringByReplacingOccurrencesOfString:@" " withString:@""];
storyLink = [storyLink stringByReplacingOccurrencesOfString:@"\n" withString:@""];
storyLink = [storyLink stringByReplacingOccurrencesOfString:@" " withString:@""];
[tableView deselectRowAtIndexPath:indexPath animated:NO];
browserScreen = [[DetailsViewController alloc] initWithNibName:@"DetailsViewController" bundle:nil];
[self.view addSubview:browserScreen.view];
// open in Safari --> this line works perfect but I want to open the link in my own Webview so I commented it out
//[[UIApplication sharedApplication] openURL:[NSURL URLWithString:storyLink]];
}
感謝您的幫助!
謝謝,但沒有奏效,我的問題在於使用storyLink作爲全局字符串。 webView在DetailsViewController中看不到storyLink – user1279453
我找到了另一個解決方案,我需要的是使用globel字符串將「storyLink」傳遞給webView。儘管如此,非常感謝您抽出時間 – user1279453