cin向C++中的向量

Question

這就是我的程序的工作原理。它提示用戶輸入，一旦檢測到非數字，循環將停止。這裏是我的代碼：

int size = 0; 
float number; 
float total = 0; 
vector <float> data; 

//prompt user to enter file name 
string file; 
cout << "Enter a file name : " ; 
cin >> file ; 
//concatenate the file name as text file 
file += ".txt"; 

//Write file 
cout << "Enter number : "; 
ofstream out_file; 
out_file.open(file); 
while(cin >> number) 
{ 
    data.push_back(number); 
    size++; 
} 

cout<< "Elements in array are : " ; 
//check whether is there any 0 in array else print out the element in array 
for (int count = 0; count < size; count++) 
{ 
    if (data.size() == 0) 
    { 
     cout << "0 digit detected. " << endl; 
     system("PAUSE"); 
    }else 
    { 
     //write the element in array into text file 
     out_file << data.size() << " " ; 
     cout << data.size() << " "; 
    } 
} 
out_file.close(); 

但是，有一些錯誤。例如，我輸入1,2,3,4,5，g，它應該把數組寫成1,2,3,4,5到文本文件中。但是，它用5,5,5,5,5代替。我在想我是否錯誤地使用了push_back？任何指南，將不勝感激。

在此先感謝。

Answer 1

for (int count = 0; count < data.size(); count++) { 
    if (data[count] == 0) { 
     cout << "0 digit detected. " << endl; 
     system("PAUSE"); 
    } else { 
     //write the element in array into text file 
     out_file << data[count] << " " ; 
     cout << data[count] << " "; 
    } 
} 
out_file.close(); 

使用元素而不是矢量的大小。例如：

std::vector<int> yourVector; 

yourVector.push_back(1); 
yourVector.push_back(3); 

cout << "My vector size: " << yourVector.size() << endl; //This will give 2 

cout << "My vector element: " << yourVector[0] << endl; //This will give 1 

Answer 2

這條線路是你要去哪裏錯了：

out_file << data.size() << " " ; 

您只需插入載體，而不是在條目中的數據的大小...

（事實上你只是檢查data.size()）