四捨五入日期

Question

說我是在看一個特定日期：

from datetime import date, timedelta 
days_to_substract = 65 
my_date = date.today()-timedelta(days=days_to_subtract) 

我如何才能找到：

1. 的Monday的my_date前右側的日期（如果my_date不是星期一）
2. 最接近Monday至my_date

日期

有沒有辦法將datetime中的日期倒圓？

Answer 1

可以使用dateutil

from datetime import * 
from dateutil.relativedelta import * 

days_to_substract = 64 
my_date = (date.today()-timedelta(days=days_to_substract)) 
next=my_date+relativedelta(weekday=MO) 
previous=my_date+relativedelta(weekday=MO(-1)) 
print ('mydate is %s' %my_date) 
print ('next monday is %s' %next) 
print ('previous monday is %s' %previous) 

diff1=my_date-previous 
diff2=next-my_date 
if diff2<diff1: 
    print ('Closest monday is %s' %next) 
else: 
    print ('Closest monday is %s' %previous) 

將輸出：

mydate is 2014-01-21 
next monday is 2014-01-27 
previous monday is 2014-01-20 
Closest monday is 2014-01-20 

Answer 2

使用平日：

from datetime import date, timedelta 
d=["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"] 
days_to_substract = 65 
my_date = (date.today()-timedelta(days=days_to_substract)) 
t=my_date.weekday() 
print "Today is ",d[t]," Wait ",(6-t+1)," days for Monday" 

輸出：

Today is Monday Wait 7 days for Monday 

Answer 3

您可以使用date.weekday（http://docs.python.org/2/library/datetime.html#datetime.date.weekday）查找「my_date」的weekday整數值。然後，您可以使用當前工作日的差異（例如星期三的星期幾= 2）並執行另一個時間點計算。這對我工作時，我試過了：

from datetime import * 

days_to_subtract = 65 
my_date = (date.today() - timedelta(days=days_to_subtract)) 
dow = my_date.weekday() 
monday_my_date = (my_date - timedelta(days=dow)) 

print(monday_my_date) 

好運！