PHP Curl - 如何做POST請求和參數應該是JSON格式的正文

我需要在PHP curl中複製相同的POST請求。請求參數應該在json中，響應也是json對象。PHP Curl - 如何做POST請求和參數應該是JSON格式的正文

Fiddler sample

{ 
"api_key": "scTrCT", 
"test": "true", 
"service_provider_list": [ 
    { 
     "facility_name": "ALL YOUR SMILE NEEDS DENTAL CENTERS", 
     "provider_name": "DRS. HERMAN AND MACK P.C", 
     "tax_id": "12345678 
    } 
], 
"payer_ids": [ 
    "00431" 
], 
"transaction_type": "270", 
"effective_date": "2014-01-12" 
}

來源

2014-01-16 Anand

請試試這個：

<?php 

$json = array(
    "api_key" => "scTrCT", 
    "test" => "true", 
    "service_provider_list" => array(
     "facility_name" => "ALL YOUR SMILE NEEDS DENTAL CENTERS", 
     "provider_name" => "DRS. HERMAN AND MACK P.C", 
     "tax_id" => "12345678" 
    ), 
    "payer_ids" => array(
     "00431" 
    ), 
    "transaction_type" => "270", 
    "effective_date" => "2014-01-12" 
); 

$json = json_encode($json); 

$ch = curl_init('http://gds.eligibleapi.com/v1.3/enrollment.json'); 
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); 
curl_setopt($ch, CURLOPT_POSTFIELDS, $json); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
$result = curl_exec($ch); 
curl_close($ch); 

echo $result;

來源

2014-01-16 04:42:16

這工作..謝謝..但是，當我給出錯誤的API密鑰，它重新調校錯誤代碼22.小提琴手它返回的錯誤描述作爲無效Api「。我如何獲得描述。以下是用於捕獲錯誤的代碼。 $ error = curl_errno（$ ch）; curl_close（$ ch）; if（$ error）{$ error_codes = $ this - > _ get_curl_error_codes（）; echo $ error; //。'：'。$ error_codes [$ error]; die（）; } – Anand

我很高興聽到它！我很高興你沒有真正把你真正的API密鑰。 –

如何捕獲所有異常（錯誤）？ – Anand

PHP Curl - 如何做POST請求和參數應該是JSON格式的正文

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