如何解析字典

-3

我從Web服務中獲得的字典名單如下列表：如何解析字典

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"B"}, {"user_id": null, "name": "image.size", "resource_id": "cbaa1562-c6c0-4922-b5ec-95ae71d0ebda", "source": "openstack", "meter_id": "Y2JhYTE1NjItYzZjMC00OTIyLWI1ZWMtOTVhZTcxZDBlYmRhK2ltYWdlLnNpemU=\n", "project_id": "f8bd7d5659a74eb6a6c47650a43511b5", "type": "gauge", "unit": "B"}]

我想： 1）解析這個名單成單獨的字典 2）提取值從每個字典

因此，僞代碼將是：

for listItem in my_list: 
    userId = listItem["user_id"] 
    name = listItem["name"] 
    resourceId = listItem["resource_id"]

什麼是正確的Python語法做到這一點？

來源

2014-12-03 Eugene Goldberg

這已經有效陣列的。你期望輸出什麼？ – davidism 2014-12-03 05:32:28

也許這個簡單的例子將說明：

from pprint import pprint 
import json 

json_string = '[{"name": "Jean Luc", "rank": "Captain"}, {"name": "Worf", "rank": "Commander"}]' 

officers = json.loads(json_string) 
for officer in officers: 
    pprint(officer)

你想看看Python的JSON庫[1]從字符串/文件到像列表和類型的字典正常的數據結構解析JSON。

[1] https://docs.python.org/2/library/json.html

來源

2014-12-03 05:34:42 poundifdef

這工作：json_string = stringText 類型的字典= json.loads（json_string）爲字典中類型的字典：打印（辭典[ '名稱']）打印（辭典[ 'USER_ID']）打印（辭典[ 'RESOURCE_ID' ]） – 2014-12-03 05:52:17

listItem[0]["user_id"] 
listItem[0]["name"] 
listItem[0]["resource_id"]

類似地對於下一個陣列

listItem[1]["user_id"] 
listItem[1]["name"] 
listItem[1]["resource_id"]

，並檢查長度使用

len(listItem)

來源

2014-12-03 05:36:19 Rahul

如何解析字典

回答

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