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我正在嘗試編寫線路交叉點代碼來檢測兩條線是否相交。 我有東西的形式是有O對象，可以有Lo（l下標O）線，每行有2個點，每個點有一個x和一個y。 這是記錄格式。pascal中的線路交叉點代碼
TPoint = record
x,y:integer;
end;
TLine = record
Point : array[0..1] of TPoint;
Color : Tcolor;
end;
TFill = record
Point : TPoint;
Color : Tcolor;
end;
TDObject = record
Lines : array of TLine;
Fills : array of TFill;
Rotation : integer;
Position : Tpoint;
BoundTop,Boundleft,Boundbottom,Boundright:integer;
end;
我調用Code來遍歷我希望測試碰撞的兩個對象的每個行組合。
Function DoCollide(obj1,obj2:Tdobject):boolean;
var i,j:integer;
coll:boolean;
begin
coll:=false;
for i:=0 to length(obj1.lines) do
begin
for j:=0 to length(obj2.lines) do
begin
coll:=DoesIntersect(obj2.lines[i],obj2.lines[j])or coll;
end;
end;
result:=coll;
end;
各行測試，像這樣
Function DoesIntersect(Line1,Line2:Tline):boolean;
var
m1,m2,c1,c2,intersect:real;
v1,v2:Boolean;
begin
//return true if lines cross
// if line if verticle do not workout gradient
if ((line1.point[1].x)-(line1.point[0].x))=0 then
v1:=true // remember line 1 is verticle
else
begin
m1 := ((line1.point[1].y)-(line1.point[0].y))/((line1.point[1].x)-(line1.point[0].x));
c1 := line1.point[0].y - (line1.point[0].x*m1);
end;
if ((line2.point[1].x)-(line2.point[0].x))=0 then
v2:=true // remember line 2 is verticle
else
begin
m2 := ((line2.point[1].y)-(line2.point[0].y))/((line2.point[1].x)-(line2.point[0].x));
c2 := line2.point[0].y - (line2.point[0].x*m2);
end;
if ((NOT(m1=m2)) and (NOT(v1 or v2))) then // non parrellel and non verticle
begin
//lines cross find where
intersect := (c2-c1)/(m1-m2); //line intersect solved for x
if ((round(intersect)>= Min(line1.point[0].x,line1.point[1].x))
and(round(intersect)<=max(line1.point[0].x,line1.point[1].x))
and(round(intersect)>=min(line2.point[0].x,line2.point[1].x))
and(round(intersect)<=max(line2.point[0].x,line2.point[1].x))) then
result := true
else
result := false
end
else if (v1 and v2) then // both lines are parralel
begin
// double verticle parallel exeption
if (((line1.Point[0].y>=min(line2.Point[0].y,line2.Point[1].y))
and(line1.Point[0].y<=max(line2.Point[0].y,line2.Point[1].y)))
or ((line1.Point[1].y>=min(line2.Point[0].y,line2.Point[1].y))
and(line1.Point[1].y<=max(line2.Point[0].y,line2.Point[1].y)))
or ((line2.Point[0].y>=min(line1.Point[0].y,line1.Point[1].y))
and(line2.Point[0].y<=max(line1.Point[0].y,line1.Point[1].y)))
or ((line2.Point[1].y>=min(line1.Point[0].y,line1.Point[1].y))
and(line2.Point[1].y<=max(line1.Point[0].y,line1.Point[1].y)))) then
result := true
else
result := false;
end
else if (v1 and not v2) then // line 1 is verticle and line 2 is not
begin
if ((((line1.Point[0].x*m2+c2)>=min(line1.Point[0].y,line1.Point[1].y))
and ((line1.Point[0].x*m2+c2)<=max(line1.Point[0].y,line1.Point[1].y)))) then
result := true
else
result := false
end
else if (v2 and not v1) then // line 2 is verticle and line 1 is not
begin
if (((line2.Point[0].x*m1+c1)>min(line2.Point[0].y,line2.Point[1].y))
and ((line2.Point[0].x*m1+c1)<max(line2.Point[0].y,line2.Point[1].y))) then
result := true
else
result := false
end
else if (m1=m2) then // parrellel non verticle lines
begin
if (((line1.Point[0].x>=min(line2.Point[0].x,line2.Point[1].x))
and(line1.Point[0].x<=max(line2.Point[0].x,line2.Point[1].x)))
or ((line1.Point[1].x>=min(line2.Point[0].x,line2.Point[1].x))
and(line1.Point[1].x<=max(line2.Point[0].x,line2.Point[1].x)))
or ((line2.Point[0].x>=min(line1.Point[0].x,line1.Point[1].x))
and(line2.Point[0].x<=max(line1.Point[0].x,line1.Point[1].x)))
or ((line2.Point[1].x>=min(line1.Point[0].x,line1.Point[1].x))
and(line2.Point[1].x<=max(line1.Point[0].x,line1.Point[1].x)))) then
result := true
else
result := false;
end;
end;
完成，但根據我的所有代碼行總是相交.....因此，我犯了一個錯誤......我在一個做這個愚蠢的方式任何想法我做錯了什麼？