如何創建嵌套的php對象

Question

我想創建一個具有以下圖層的php對象。

$obj->property->name; 
$obj->property->title; 
$obj->property->id; 
$obj->property->height; 

這給我 'Trying to get property of non-object' 錯誤

我的目標

$obj = [ 
    'property' => [ 
     'name' => 'Rick', 
     'title' => 'manager', 
     'id' => '123', 
     'height' => '5.6' 
    ] 
]; 

$obj = = (object)$obj; 

我不知道正確的語法產生$obj->property->name;任何人都可以幫我嗎？我的大腦被解僱了......謝謝！

Answer 1

你應該投 到object也property：

$obj = [ 
    'property' => [ 
     'name' => 'Rick', 
     'title' => 'manager', 
     'id' => '123', 
     'height' => '5.6' 
    ] 
]; 

$object = (object)$obj; 
$object->property = (object)$object->property; 

結果：

var_dump($object->property->id); // string(3) "123" 
var_dump($object->property->name); // string(4) "Rick" 
// etc. 

Answer 2

你有property object一個數組裏面，你可以不喜歡這樣

$obj->property->name; 

使用這應該是：

$obj->property['name']; 

例子：

$yourArr = array('property'=>array(
     'name' => 'Rick', 
     'title' => 'manager', 
     'id' => '123', 
     'height' => '5.6' 
    )); 

$yourObj = (object) $yourArr; 
echo $yourObj->property['name']; // Rick