jQuery：選擇框不響應

選擇選擇框時，我想從數據庫中創建一個<input type="text"></input>放置文本。這裏是我的jQuery代碼jQuery：選擇框不響應

<script type="text/javascript" src="jquery.js"></script> 
<script> 
    $(document).ready(function() { 
    $('#noID').change(function() { 
     var noID = $(this).val(); 
      $.ajax({ 
       type: 'POST', 
       url: 'ambilusername.php', 
       data: 'noID=' + noID, 
       success: function(response) { 
       $('#username').val(response); 
       } 
      }); 
     }); 
    }); 
</script>

，這裏是我的「ambilusername.php」

<?php 
include "../include/koneksi_db.php"; 

$noID = $_POST["noID"]; 
$username = mysql_query("SELECT * FROM booking_tamu WHERE noID='$noID'"); 
while($k = mysql_fetch_array($username)){ 
    echo "$k[email]"; 
} 
?>

這裏是我的全部的index.php代碼：

<?php 

include "../include/koneksi_db.php"; 

?> 
<html> 
<head> 
    <script type="text/javascript" src="jquery.js"></script> 
    <script> 
     $(document).ready(function() { 
     $('#noID').change(function() { 
      var noID = $(this).val(); 
       $.ajax({ 
        type: 'POST', 
        url: 'ambilusername.php', 
        data: 'noID=' + noID, 
        success: function(response) { 
        $('#username').val(response); 
        } 
       }); 
      }); 
     }); 
    </script> 
</head> 
<body> 
<form method="post" action="?page=prosesTambahAkun"> 
<table class="table-data" width=100% border=1> 
    <tr><td colspan="2" class="head-data">Tambah Data Akun</td></tr> 
    <tr> 
    <td class="pinggir-data">ID Pemesan</td> 
    <td> 
     <select name="noID" id="noID" required> 
      <option value="">------Pilih ID Pemesan------</option> 
       <?php 
        $query = "SELECT no_booking, COUNT(no_booking) AS 'jumlah' FROM booking_tamu GROUP BY no_booking ASC"; 
        $hasil = mysql_query($query); 
        while ($data = mysql_fetch_array($hasil)){ 
        echo "<option value='".$data['no_booking']."'>".$data['no_booking']."</option>"; 
        } 
       ?> 
     </select> 
    </td> 
    </tr> 
    <tr> 
    <td class="pinggir-data">Username</td> 
    <td> 
     <input type="text" id="username" name="username" size="30px" readonly></input> 
    </td> 
    </tr> 

    <tr><td colspan="2" align="center" class="head-data"> 
     <input type="submit" value="Tambah" name="tambah"> 
    </td></tr> 
</table> 
</form> 
</body> 
</html>

的問題是，當我選擇在選擇框上的值，文本框不會把東西放在它上面。你能幫我麼？

來源

2015-06-12 PhaskalRolando

的問題是你的表列的命名：

改變這一點：

$username = mysql_query("SELECT * FROM booking_tamu WHERE noID='$noID'");

這樣：

$username = mysql_query("SELECT * FROM booking_tamu WHERE no_booking='$noID'");

來源

2015-06-12 18:52:23 CodeGodie

jQuery：選擇框不響應

回答

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