如果條件爲真，則返回幾行

Question

假設我有這個簡單的if-elsif-else代碼塊。

def 
    # some code... 
    input = get.chomp 
    if input == 1 
    puts "foo" 
    elsif input == 2 
    puts "bar" 
    else 
    # exit 
    end 
    # some more code... 
end 

我如何告訴節目回去，並再次要求輸入病例1和2並在此方法中，代碼繼續，如果else被觸發？我不想回到開始的方法，而是我只想回到input變量聲明。

Answer 1

def 
    # some code... 
    loop do 
    input = get.chomp 
    if input == 1 
     puts "foo" 
     break 
    elsif input == 2 
     puts "bar" 
     break 
    end 
    end 
    # some more code... 
end 

注：您的兩個if/elsif條件將永遠無法滿足。

Answer 2

# main procedure 
# defined here so other functions could be declared after 
# the main procedure is called at the bottom 
def main 

    loop do 
    puts "Insert a number" 
    input = gets.chomp.to_i 

    if isValidInput input 
     puts case input 
     when 1 
      "foo" 
     when 2 
      "bar" 
     end 
     break 
    end 
    end #loop 

    puts "Other code would execute here" 

end 

# Validity Checker 
# makes sure your input meets your condition 
def isValidInput(input) 
    if [1,2].include? input 
    return true 
    end 
    return false 
end 


main