insert ...在選擇錯誤時用分隔符選擇？

CREATE TABLE IF NOT EXISTS XY（ X INT NOT NULL， ÿFLOAT NULL， PRIMARY KEY（x）的）insert ...在選擇錯誤時用分隔符選擇？

INSERT INTO XY (x,y) 
(select 1 as x ,(1/7) as y);

錯誤與

Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO XY (x,y) 
(select 1 as x ,(1/7) as y)' at line 7 
Line 1, column 1

什麼想法？

來源

2010-06-07 Mark

您應該添加括號;之後CREATE TABLE聲明（或在INSERT聲明之前）。您正在嘗試執行2個不含分隔符的不同查詢。

CREATE TABLE IF NOT EXISTS XY (
x INT NOT NULL , 
y FLOAT NULL , 
PRIMARY KEY(x) 
); # !!! Originally, you missed ; 

INSERT INTO XY (x,y) 
(select 1 as x ,(1/7) as y);

來源

2010-06-07 18:06:40 a1ex07

沒有區別嘗試，這是在找出爲什麼這個查詢不工作， INSERT INTO resultprobability（ballNumber，概率）嘗試（選擇resultset.ballNumber ballNumber，（計數（0）/（從結果集中選擇計數（0）））概率 from resultset group by resultset.ballNumber）; – Mark 2010-06-07 18:19:30

你需要周圍的select語句

INSERT INTO XY (x,y) 
select 1 as x ,(1/7) as y;

來源

2010-06-07 18:01:50 SQLMenace

我已經有和沒有錯誤 – Mark 2010-06-07 18:03:44

insert ...在選擇錯誤時用分隔符選擇？

回答

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