Android重命名設備的名稱爲wifi-direct

Question

我想連接兩個使用Wifi Direct的設備，但我想以編程方式而不是由用戶發起。

爲此，我不得不改變設備的Wi-Fi直連的名稱，如下面的圖片：通過下面的代碼

wifiP2pManager.discoverPeers(channel, 
       new WifiP2pManager.ActionListener() { 

        @Override 
        public void onSuccess() { 
         Log.d(TAG, "onSuccess"); 
        } 

        @Override 
        public void onFailure(int reason) { 
         Log.d(TAG, "onFailure"); 
        } 
       }); 

連接到特定的同行：

使用下面的方法現在發現對等

public static void connectPeer(WifiP2pDevice device, 
     WifiP2pManager manager, Channel channel, final Handler handler) { 

    WifiP2pConfig config = new WifiP2pConfig(); 
    config.groupOwnerIntent = 15; 
    config.deviceAddress = device.deviceAddress; 
    config.wps.setup = WpsInfo.PBC; 

    manager.connect(channel, config, new ActionListener() { 

     @Override 
     public void onSuccess() { 

     } 

     @Override 
     public void onFailure(int reason) { 

     } 
    }); 
} 

但我沒有k現在如何更改Wi-Fi Direct的設備名稱？

Answer 1

即使我不建議使用反射來訪問WifiP2pManager中隱藏的API，這對我來說也是有效的。

public void setDeviceName(String devName) { 
    try { 
     Class[] paramTypes = new Class[3]; 
     paramTypes[0] = Channel.class; 
     paramTypes[1] = String.class; 
     paramTypes[2] = ActionListener.class; 
     Method setDeviceName = manager.getClass().getMethod(
       "setDeviceName", paramTypes); 
     setDeviceName.setAccessible(true); 

     Object arglist[] = new Object[3]; 
     arglist[0] = channel; 
     arglist[1] = devName; 
     arglist[2] = new ActionListener() { 

      @Override 
      public void onSuccess() { 
       LOG.debug("setDeviceName succeeded"); 
      } 

      @Override 
      public void onFailure(int reason) { 
       LOG.debug("setDeviceName failed"); 
      } 
     }; 

     setDeviceName.invoke(manager, arglist); 

    } catch (NoSuchMethodException e) { 
     e.printStackTrace(); 
    } catch (IllegalAccessException e) { 
     e.printStackTrace(); 
    } catch (IllegalArgumentException e) { 
     e.printStackTrace(); 
    } catch (InvocationTargetException e) { 
     e.printStackTrace(); 
    } 

}