Question

我在這個問題上關注了很多例子，但我似乎無法得到這個工作。 我可以單獨查詢成功的數據庫，但不能查詢同一查詢中的兩個數據庫。

我試過別名，指的是查詢中的服務器......把名字放在名字周圍等等。

所以這是我的代碼

連接字符串：

/// LOCAL DATABASE 
$databaseprefix = "w-"; 
$mysqlHost = 'localhost'; 
$mysqlUser = 'web123-USER1'; 
$mysqlPass = 'SOMEPASSWORD'; 
$mysqlDB = $databaseprefix . 'DATABASE1'; 
$conn = mysql_connect($mysqlHost,$mysqlUser,$mysqlPass,true) or die('Could not connect to SQL Server on '.$mysqlHost.' '. mysql_error()); 

///select remote database to work with 
$localDB = mysql_select_db($mysqlDB, $conn) or die("x1 Couldn't open database $mysqlDB"); 

///////////// GET THE DATABASE WE WANT TO EDIT 
$remoteHost = $_SESSION['localfolder']; 
$remoteUser = $_SESSION['databaseuser']; 
$remotePass = $_SESSION['databasepassword']; 
$remoteDB = $_SESSION['database']; 
$remoteconn = mysql_connect($remoteHost,$remoteUser,$remotePass,true) or die('Could not connect to SQL Server on '.$remoteHost.' '. mysql_error()); 

$clientDB = mysql_select_db($remoteDB, $remoteconn) or die("x2 Couldn't open database $remoteDB"); 

好的話，我有這個

$query_string = "select 
`$remoteHost`.`$remoteDB`.`pages`.`page_title`, 
`$mysqlHost`.`$mysqlDB`.`c_users`.`name` 
from `$remoteHost`.`$remoteDB`.`pages` 
left join `$mysqlHost`.`$mysqlDB`.`c_users` 
on `$remoteHost`.`$remoteDB`.`pages`.`created_by` = `$mysqlHost`.`$mysqlDB`.`c_users`.`user_id`"; 

echo $query_string; 
//// Query the DB's 
$query = mysql_query($query_string); 

echo mysql_num_rows($query); 

while($row = mysql_fetch_assoc($query)) { 
    echo $row['name'] . ' | ' . $row['page_title']; 
} 

從查詢的輸出是這樣的

select `remoteaddress.co.uk`.`remote-DB`.`pages`.`page_title`, 
`localhost`.`w-DATABASE1`.`c_users`.`name` 
from `remoteaddress.co.uk`.`remote-DB`.`pages` 
left join `localhost`.`w-DATABASE1`.`c_users` on 
`remoteaddress.co.uk`.`remote-DB`.`pages`.`created_by` = `localhost`.`w-DATABASE1`.`c_users`.`user_id` 

兩者連接字段是聯接上的INT數據類型和相同的排序規則。我不確定爲什麼會失敗。任何幫助，將不勝感激。

Answer 1

那是因爲你的本地連接無法直接連接到遠程主機...

您可以使用2個查詢，每一個服務器，而不是

$query = mysql_query($query_string, $conn); 
$query = mysql_query($query_string, $remoteconn);