什麼Regex可以去除例如字符串左邊的「note：」和「firstName：」？

Question

我需要剝去「標籤」斷開串的前部，例如

注：這是一個註解

需要返回：

注

和

這是一記

我產生了以下的代碼示例但我有與正則表達式的麻煩。

我需要在這兩個是什麼代碼????????下面的區域，以便我可以在評論中看到所需的結果？

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Text.RegularExpressions; 

namespace TestRegex8822 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      List<string> lines = new List<string>(); 
      lines.Add("note: this is a note"); 
      lines.Add("test: just a test"); 
      lines.Add("test:\t\t\tjust a test"); 
      lines.Add("firstName: Jim"); //"firstName" IS a label because it does NOT contain a space 
      lines.Add("She said this to him: follow me."); //this is NOT a label since there is a space before the colon 
      lines.Add("description: this is the first description"); 
      lines.Add("description:this is the second description"); //no space after colon 
      lines.Add("this is a line with no label"); 

      foreach (var line in lines) 
      { 
       Console.WriteLine(StringHelpers.GetLabelFromLine(line)); 
       Console.WriteLine(StringHelpers.StripLabelFromLine(line)); 
       Console.WriteLine("--"); 
       //note 
       //this is a note 
       //-- 
       //test 
       //just a test 
       //-- 
       //test 
       //just a test 
       //-- 
       //firstName 
       //Jim 
       //-- 
       // 
       //She said this to him: follow me. 
       //-- 
       //description 
       //this is the first description 
       //-- 
       //description 
       //this is the first description 
       //-- 
       // 
       //this is a line with no label 
       //-- 

      } 
      Console.ReadLine(); 
     } 
    } 

    public static class StringHelpers 
    { 
     public static string GetLabelFromLine(this string line) 
     { 
      string label = line.GetMatch(@"^?:(\s)"); //??????????????? 
      if (!label.IsNullOrEmpty()) 
       return label; 
      else 
       return ""; 
     } 

     public static string StripLabelFromLine(this string line) 
     { 
      return ...//??????????????? 
     } 

     public static bool IsNullOrEmpty(this string line) 
     { 
      return String.IsNullOrEmpty(line); 
     } 
    } 

    public static class RegexHelpers 
    { 
     public static string GetMatch(this string text, string regex) 
     { 
      Match match = Regex.Match(text, regex); 
      if (match.Success) 
      { 
       string theMatch = match.Groups[0].Value; 
       return theMatch; 
      } 
      else 
      { 
       return null; 
      } 
     } 
    } 
} 

新增

@Keltex，我納入你的想法如下，但它不匹配任何文本（所有條目是空白的），請問我需要在正則表達式來調整？

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Text.RegularExpressions; 

namespace TestRegex8822 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      List<string> lines = new List<string>(); 
      lines.Add("note: this is a note"); 
      lines.Add("test: just a test"); 
      lines.Add("test:\t\t\tjust a test"); 
      lines.Add("firstName: Jim"); //"firstName" IS a label because it does NOT contain a space 
      lines.Add("first name: Jim"); //"first name" is not a label because it contains a space 
      lines.Add("description: this is the first description"); 
      lines.Add("description:this is the second description"); //no space after colon 
      lines.Add("this is a line with no label"); 

      foreach (var line in lines) 
      { 
       LabelLinePair llp = line.GetLabelLinePair(); 
       Console.WriteLine(llp.Label); 
       Console.WriteLine(llp.Line); 
       Console.WriteLine("--"); 
      } 
      Console.ReadLine(); 
     } 
    } 

    public static class StringHelpers 
    { 
     public static LabelLinePair GetLabelLinePair(this string line) 
     { 
      Regex regex = new Regex(@"(?<label>.+):\s*(?<text>.+)"); 
      Match match = regex.Match(line); 
      LabelLinePair labelLinePair = new LabelLinePair(); 
      labelLinePair.Label = match.Groups["label"].ToString(); 
      labelLinePair.Line = match.Groups["line"].ToString(); 
      return labelLinePair; 
     } 
    } 

    public class LabelLinePair 
    { 
     public string Label { get; set; } 
     public string Line { get; set; } 
    } 

} 

解決：

好吧，我得到它的工作，再加上加了一點黑客採取用空格標籤的關懷和它正是我想要的，謝謝！

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Text.RegularExpressions; 

namespace TestRegex8822 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      List<string> lines = new List<string>(); 
      lines.Add("note: this is a note"); 
      lines.Add("test: just a test"); 
      lines.Add("test:\t\t\tjust a test"); 
      lines.Add("firstName: Jim"); //"firstName" IS a label because it does NOT contain a space 
      lines.Add("first name: Jim"); //"first name" is not a label because it contains a space 
      lines.Add("description: this is the first description"); 
      lines.Add("description:this is the second description"); //no space after colon 
      lines.Add("this is a line with no label"); 
      lines.Add("she said to him: follow me"); 

      foreach (var line in lines) 
      { 
       LabelLinePair llp = line.GetLabelLinePair(); 
       Console.WriteLine(llp.Label); 
       Console.WriteLine(llp.Line); 
       Console.WriteLine("--"); 
      } 
      Console.ReadLine(); 
     } 
    } 

    public static class StringHelpers 
    { 
     public static LabelLinePair GetLabelLinePair(this string line) 
     { 
      Regex regex = new Regex(@"(?<label>.+):\s*(?<text>.+)"); 
      Match match = regex.Match(line); 
      LabelLinePair llp = new LabelLinePair(); 
      llp.Label = match.Groups["label"].ToString(); 
      llp.Line = match.Groups["text"].ToString(); 

      if (llp.Label.IsNullOrEmpty() || llp.Label.Contains(" ")) 
      { 
       llp.Label = ""; 
       llp.Line = line; 
      } 

      return llp; 
     } 

     public static bool IsNullOrEmpty(this string line) 
     { 
      return String.IsNullOrEmpty(line); 
     } 
    } 

    public class LabelLinePair 
    { 
     public string Label { get; set; } 
     public string Line { get; set; } 
    } 

} 

Answer 1

它可能是這樣的：

Regex myreg = new Regex(@"(?<label>.+):\s*(?<text>.+)"); 

Match mymatch = myreg.Match(text); 

if(mymatch.IsMatch) 
{ 
    Console.WriteLine("label: "+mymatch.Groups["label"]); 
    Console.WriteLine("text: "+mymatch.Groups["text"]); 
} 

我用上面的命名相匹配，但你可以沒有他們。另外，我認爲這比做兩個方法調用更有效率。一個正則表達式獲得文本和標籤。

Answer 2

不能你只是劈在第一個冒號的字符串，或者如果沒有冒號沒有標籤？

public static class StringHelpers 
{ 
    public static string GetLabelFromLine(this string line) 
    { 
     int separatorIndex = line.IndexOf(':'); 
     if (separatorIndex > 0) 
     { 
      string possibleLabel = line.Substring(0, separatorIndex).Trim(); 
      if(possibleLabel.IndexOf(' ') < 0) 
      { 
       return possibleLabel; 
      } 
     } 
     else 
     { 
      return string.Empty; 
     }   
    } 

    public static string StripLabelFromLine(this string line) 
    { 
     int separatorIndex = line.IndexOf(':'); 
     if (separatorIndex > 0) 
     { 
      return line.Substring(separatorIndex + 1, 
        line.Length - separatorIndex - 1).Trim(); 
     } 
     else 
     { 
      return line; 
     }  
    } 

    public static bool IsNullOrEmpty(this string line) 
    { 
     return String.IsNullOrEmpty(line); 
    } 
} 

Answer 3

此正則表達式的作品（see it in action on rubular）：

(?: *([^:\s]+) *: *)?(.+) 

這抓住了標籤，如果有的話，到\1，與身體成\2。

它有足夠津貼空格，所以標籤可以縮進等