如何從嵌套的JSON字符串中的數組中檢索值？

如何從這個JSON字符串中的數組paramList（在name":"offset","values":["90"]的開頭）檢索值90？如何從嵌套的JSON字符串中的數組中檢索值？

{"query":{"query":"skole","hits":10,"paramList":[{"name":"hits","values":["10"]},{"name":"offset","values":["90"]},{"name":"q","values":["skole"]}]},"status":"success","facets":[{"selectionType":"AND","numberOfItems":1,"selectableItems":[{"value":"Intranett","displayName":"Intranett","count":146,"paramId":"?hits=10&q=skole&kilde=Intranett"}],"appliedItems":[],"facetName":"Kilde"},{"selectionType":"AND","numberOfItems":4,"selectableItems":[{"value":"EPiServerPage","displayName":"EPiServerPage","count":90,"paramId":"?hits=10&q=skole&type_s=EPiServerPage"},{"value":"Word","displayName":"Word","count":51,"paramId":"?hits=10&q=skole&type_s=Word"},{"value":"ClubNews","displayName":"ClubNews","count":4,"paramId":"?hits=10&q=skole&type_s=ClubNews"},{"value":"Project","displayName":"Project","count":1,"paramId":"?hits=10&q=skole&type_s=Project"}],"appliedItems":[],"facetName":"Type"}],"suggestions":{"displayName":"spellingSuggestion","suggestions":null,"collatedSuggestion":{"suggestion":null,"paramId":"?q=null"}},"errors":[],"numberOfHits":146,"pagination":{"offset":90,"first":{"displayName":"1","selected":false,"end":10,"start":1,"paramId":"?hits=10&q=skole&offset=1"},"next":{"displayName":"11","selected":false,"end":109,"start":100,"paramId":"?hits=10&q=skole&offset=100"},"hitsPerPage":10,"paginationItems":[{"displayName":"5","selected":false,"end":49,"start":40,"paramId":"?hits=10&q=skole&offset=40"},{"displayName":"6","selected":false,"end":59,"start":50,"paramId":"?hits=10&q=skole&offset=50"}, .....

爲了檢索（第一行的開始）的元件查詢我使用{$T.query.query}

來源

2012-09-12 Anders Branderud

$T.query.query.paramList[1].values[0]假設該結構不會改變

來源

2012-09-12 15:49:18

~~var val = jsonArray["query"]["paramList"][1]["values"];~~

var q = jsonArray["query"]["paramList"]; 

var values = q.map(function(){ 

    return values[0]; 

}); 

var index = values.indexOf(90);

來源

2012-09-12 15:49:51

'values'是一個數組，而這正是這個表達式會。 –

也，即使這*是正確的，它將返回10，而不是90 –

@PhillipSchmidt：對不起，更正和更新。感謝您的高舉。 –

如果您只查看特定值並知道它將在哪E在JSON，你可以使用：

var json = 'YOUR JSON STRING HERE'; 
var obj = $.parseJSON(json); 
var value = obj.query.paramList[1].values[0];

來源

2012-09-12 15:51:09

-1

你的JSON評估

JSON.query.paramList[1].values.[0];

回報90.

來源

2012-09-12 15:51:13 Stefan

嗯......這看起來很像我的答案。除了我的答案有正確的好處。 –

沒有花太多時間回答這個問題，而且我在提交答案後已經強化了。但是，有第二個查詢。 – Stefan

如何從嵌套的JSON字符串中的數組中檢索值？

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