2013-04-28 58 views
0

我試圖通過Python 2.7更新MySQL表。我已閱讀並嘗試了許多解決方案,並不斷收到錯誤消息:類型錯誤:格式化錯誤「TypeError:並非在字符串格式化過程中轉換的所有參數」MySQLdb

import MySQLdb 
import jellyfish 

db = MySQLdb.connect('localhost','root','12badger12','group2') 
cursor = db.cursor() 

sql_com_dept = "SELECT id, bus_name FROM com_dept" 

sql_tex = "SELECT company_name FROM tex" 

score = 0 

cursor.execute(sql_tex) 

company_count = 10 

while company_count >= 1: 

    tex_tup = cursor.fetchone() 
    company_name = tex_tup 
    company = str(company_name) 

    cursor.execute(sql_com_dept) 

    dept_count = 10 

    while dept_count >= 1: 

     dept_tup = cursor.fetchone() 
     dept_name = dept_tup 
     dept = str(dept_name) 

     lev = jellyfish.levenshtein_distance(dept, company) 
     jar = jellyfish.jaro_distance(dept, company) 
     dam = jellyfish.damerau_levenshtein_distance(dept, company) 

     score_in = (lev + jar + dam)/3 

     if score_in >= score: 
      base_name = dept 
      base_id = dept_id 
      score = score_in      
     else: 
      pass 

     dept_count = dept_count - 1 

    cursor.execute("UPDATE tex SET base_name = $s WHERE company_name = $s", 
    (base_name, company_name,)) 
    db.commit() 

    company_count = company_count - 1 
    print company_count 

cursor.close() 
db.close() 
print "Matching Complete!!!" 

如何更新領域BASE_NAME字符串轉換的過程中不是所有的參數?
我是編程新手,非常感謝您的幫助。

謝謝。

回答

2

我敢肯定MySQLdb的預計%s而不是$s佔位符...

cursor.execute("UPDATE tex SET base_name = %s WHERE company_name = %s", 
       (base_name, company_name,)) 
相關問題