0
正確的我工作在yii 2.0試圖修改登錄系統。它適用於用戶只是手動編碼的數組。相反，我想從數據庫中完成這項工作。Yii 2.0從數據庫登錄不起作用
我會告訴你的初始模型的樣子：
<?php
namespace app\models;
class User extends \yii\base\Object implements \yii\web\IdentityInterface
{
public $id;
public $username;
public $password;
public $authKey;
public $accessToken;
private static $users = [
'100' => [
'id' => '100',
'username' => 'admin',
'password' => 'admin',
'authKey' => 'test100key',
'accessToken' => '100-token',
],
'101' => [
'id' => '101',
'username' => 'demo',
'password' => 'demo',
'authKey' => 'test101key',
'accessToken' => '101-token',
],
];
/**
* @inheritdoc
*/
public static function findIdentity($id)
{
return isset(self::$users[$id]) ? new static(self::$users[$id]) : null;
}
/**
* @inheritdoc
*/
public static function findIdentityByAccessToken($token, $type = null)
{
foreach (self::$users as $user) {
if ($user['accessToken'] === $token) {
return new static($user);
}
}
return null;
}
/**
* Finds user by username
*
* @param string $username
* @return static|null
*/
public static function findByUsername($username)
{
foreach (self::$users as $user) {
if (strcasecmp($user['username'], $username) === 0) {
return new static($user);
}
}
return null;
}
/**
* @inheritdoc
*/
public function getId()
{
return $this->id;
}
/**
* @inheritdoc
*/
public function getAuthKey()
{
return $this->authKey;
}
/**
* @inheritdoc
*/
public function validateAuthKey($authKey)
{
return $this->authKey === $authKey;
}
/**
* Validates password
*
* @param string $password password to validate
* @return boolean if password provided is valid for current user
*/
public function validatePassword($password)
{
return $this->password === $password;
}
}
好所以你可以看到它正在對手工編碼陣列名爲$用戶。所以我做了一個名爲「用戶」的表，並將列標識爲用戶名密碼authkey和accessToken。
希望它會做同樣的事情用一個數據庫表，當我嘗試登錄，但是我收到一個錯誤。這是我的新代碼
<?php
namespace app\models;
/**
* This is the model class for table "Cases".
*
* @property integer $id
* @property string $username
* @property string $password
* @property string $authkey
* @property string $accessToken
*/
class User extends \yii\db\ActiveRecord
{
/**
* @inheritdoc
*/
public static function tableName()
{
return 'users';
}
public function rules()
{
return [
[['id','username','password','authkey','accessToken'], 'required'],
[['id'], 'integer'],
];
}
/**
* @inheritdoc
*/
public function attributeLabels()
{
return [
'id' => 'id',
'username' => 'username',
'password' => 'password',
'authkey' => 'authkey',
'accessToken' => 'accessToken',
];
}
/**
* @inheritdoc
*/
public static function findIdentity($id)
{
return isset(self::$users[$id]) ? new static(self::$users[$id]) : null;
}
/**
* @inheritdoc
*/
public static function findIdentityByAccessToken($token, $type = null)
{
foreach (self::$users as $user) {
if ($user['accessToken'] === $token) {
return new static($user);
}
}
return null;
}
/**
* Finds user by username
*
* @param string $username
* @return static|null
*/
public static function findByUsername($username)
{
foreach (self::$Users as $user) {
if (strcasecmp($user['username'], $username) === 0) {
return new static($user);
}
}
return null;
}
/**
* @inheritdoc
*/
public function getId()
{
return $this->id;
}
/**
* @inheritdoc
*/
public function getAuthKey()
{
return $this->authKey;
}
/**
* @inheritdoc
*/
public function validateAuthKey($authKey)
{
return $this->authKey === $authKey;
}
/**
* Validates password
*
* @param string $password password to validate
* @return boolean if password provided is valid for current user
*/
public function validatePassword($password)
{
return $this->password === $password;
}
}
錯誤消息我收到的時候我嘗試登錄是「訪問未聲明的靜態屬性：應用程序\模型\用戶:: $用戶」。
如果您需要查看我的LoginForm模型和控制器操作，我會在這裏下載它們。
public function actionLogin()
{
if (!\Yii::$app->user->isGuest) {
return $this->goHome();
}
$model = new LoginForm();
if ($model->load(Yii::$app->request->post()) && $model->login()) {
return $this->goBack();
} else {
return $this->render('login', [
'model' => $model,
]);
}
}
和LoginForm的模式是：
<?php
namespace app\models;
use Yii;
use yii\base\Model;
/**
* LoginForm is the model behind the login form.
*/
class LoginForm extends Model
{
public $username;
public $password;
public $rememberMe = true;
private $_user = false;
/**
* @return array the validation rules.
*/
public function rules()
{
return [
// username and password are both required
[['username', 'password'], 'required'],
// rememberMe must be a boolean value
['rememberMe', 'boolean'],
// password is validated by validatePassword()
['password', 'validatePassword'],
];
}
/**
* Validates the password.
* This method serves as the inline validation for password.
*
* @param string $attribute the attribute currently being validated
* @param array $params the additional name-value pairs given in the rule
*/
public function validatePassword($attribute, $params)
{
if (!$this->hasErrors()) {
$user = $this->getUser();
if (!$user || !$user->validatePassword($this->password)) {
$this->addError($attribute, 'Incorrect username or password.');
}
}
}
/**
* Logs in a user using the provided username and password.
* @return boolean whether the user is logged in successfully
*/
public function login()
{
if ($this->validate()) {
return Yii::$app->user->login($this->getUser(), $this->rememberMe ? 3600*24*30 : 0);
} else {
return false;
}
}
/**
* Finds user by [[username]]
*
* @return User|null
*/
public function getUser()
{
if ($this->_user === false) {
$this->_user = User::findByUsername($this->username);
}
return $this->_user;
}
}
任何一個可以指教一下我應該做的，我再一次得到的錯誤是：
訪問未申報的靜態屬性：應用程序\型號\用戶:: $用戶
並且這個錯誤對應於這段代碼
foreach (self::$Users as $user) {
if (strcasecmp($user['username'], $username) === 0) {
return new static($user);
}
}