0
我把這個發送到web api作爲Json字符串問題:如何迭代並獲取每個數組,對象數組和對象的值?迭代JObject
generateQMEPanelRequest(date: Array<any>, text: Array<string>, checkboxes: Array<number>, personserved: IPersonServed[], qme31_7: IQme31_7): ng.IPromise<any> {
var data = {
Date: date,
Text: text,
CheckBox: checkboxes,
PersonServed: personserved,
QQME_31_7: qme31_7
};
return this.$http.post('/api/ClientForms/QMEPanelRequest',data).then(this.handleSuccess, this.handleError);
上的Web API
我得到的模型Jobject:
Model {{
"Date": [
"2017-04-03T07:00:00Z",
"2017-04-10T07:00:00Z",
"2017-06-13T07:00:00Z"
],
"Text": [
"mam",
"5445",
"MDE Dermatology"
],
"CheckBox": [
"1",
"4"
],
"PersonServed": [
{
"personId": 1,
"method": "B",
"name": "dd",
"address": "d",
"city": "d",
"state": "d",
"zipCode": "d",
"$$hashKey": "object:674"
}
],
"QQME_31_7": {
"recordsOfFirstName": "a",
"recordsOfMI": "a",
"recordsOfLastName": "dd",
"caseNo": "d",
"ownerAddress": "ddd",
"ownerState": "dd",
"ownerZip": "d"
}
}}
public IHttpActionResult QMEPanelRequest(JObject data)
{
如何迭代,並獲得值爲每個數組,對象數組和對象?
你能請張貼JSON對象爲文本,而不是圖像? – Sameer
你讀過他們的[文檔](http://www.newtonsoft.com/json/help/html/JObjectProperties.htm)嗎? – Searching