作爲一個練習(很大程度上是嘗試使用指針編寫某些東西的練習),我正在編寫一個高速緩存仿真,特別是舊的486最近使用的僞最近系統。收到「訪問衝突讀取位置」上線錯誤:C++指針「丟失」它的值
int min = treeArray[set]->root->findPLRU();
最初treeArray似乎是正確初始化(如果我在一開始暫停節目,並採取一看,這一切都爲應該是),但當程序中斷並且我深入研究事物時,沒有定義所討論的樹的根。我覺得我很可能會犯一些非常基本的指針錯誤,這會導致指向節點的指針在某處「丟失」,但我不知道它會是什麼。我需要做些什麼來「堅持」指針值?
在此先感謝您的幫助!
#include "stdafx.h"
#include "stdlib.h"
#include <conio.h>
#include <stdio.h>
#include <fcntl.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>
#include <io.h>
#include "main.h"
//char fn[80]; // trace filename
int tf; // trace file
trace buf[BUFSZ/sizeof(trace)]; // buffer SIZE
int LRUHits = 0;
int pLRUHits = 0;
int randomHits = 0;
int height;
int cachelinenumber;
//log2 helper function
int log2(int n)
{
int i = 0;
while (n)
{
n = n >> 1;
i++;
}
return i - 1;
}
class CacheLine{
public:
int tag;
int access;
CacheLine();
};
class Cache;
class Node{
public:
bool goRight;
Node* left;
Node* right;
int leftCacheLine;
int rightCacheLine;
Node(int depth) // constructor
{
goRight = false;
if (depth < height - 1)
{
left = new Node(depth + 1);
right = new Node(depth + 1);
leftCacheLine = -1;
rightCacheLine = -1;
}
else
{
leftCacheLine = cachelinenumber;
cachelinenumber++;
rightCacheLine = cachelinenumber;
cachelinenumber++;
}
//printf("Depth: %d, Height: %d, Left: %d, Right: %d\n", depth, height, leftCacheLine, rightCacheLine);
}
~Node()
{
delete left;
delete right;
}
int findPLRU()
{
if (leftCacheLine < 0 || rightCacheLine < 0)
{
if (goRight)
{
goRight = false;
return right->findPLRU();
}
else
{
goRight = true;
return left->findPLRU();
}
}
else
{
if (goRight)
{
goRight = false;
return rightCacheLine;
}
else
{
goRight = true;
return leftCacheLine;
}
}
}
};
class Tree{
public:
Node* root;
Tree()
{
root = new Node(0);
}
~Tree()
{
delete root;
}
};
//cache class
class Cache
{
public:
CacheLine *cache;
int l, k, n, replacementPolicy;
int log2l, log2n;
int access;
Tree** treeArray;
//constructor
Cache(int ll, int kk, int nn, int _replacementPolicy)
{
l = ll;
k = kk;
n = nn;
replacementPolicy = _replacementPolicy;
log2l = log2(l);
log2n = log2(n);
cache = (CacheLine*)malloc(sizeof(CacheLine)*k*n);
for (int i = 0; i < k*n; i++)
{
cache[i].tag = 0x80000000;
cache[i].access = 0;
}
if (replacementPolicy == 1)
{
cachelinenumber = 0;
treeArray = new Tree*[n];
for (int i = 0; i < n; i++)
{
treeArray[i] = new Tree();
}
}
access = -1;
}
//destructor
~Cache()
{
free(cache);
}
//test for hit
void hit(int a)
{
access++;
int set = (a >> log2l) & (n - 1);
int tag = a >> (log2n + log2l);
CacheLine* c = &cache[set*k];
for (int i = 0; i < k; i++)
{
if (c[i].tag == tag)
{
c[i].access = access;
if (replacementPolicy == 0)
LRUHits++;
else if (replacementPolicy == 1)
pLRUHits++;
else if (replacementPolicy == 2)
randomHits++;
break;
}
}
if (replacementPolicy == 0) //LRU
{
int min = 0;
int minv = c[0].access;
for (int i = 1; i < k; i++)
{
if (c[i].access < minv)
{
minv = c[i].access;
min = i;
}
}
c[min].tag = tag;
c[min].access = access;
}
else if(replacementPolicy == 1) // pseudoLRU
{
int min = treeArray[set]->root->findPLRU();
c[min].tag = tag;
c[min].access = access;
}
else // random
{
srand(clock());
int randomNumber = rand()%k;
c[randomNumber].tag = tag;
c[randomNumber].access = access;
}
return;
}
};
void analyse (int l, int k, int n)
{
height = log2(k) + 1;
char fn[] = "ico0.trace";
if ((tf = open(fn, _O_RDONLY | _O_BINARY)) == -1) {
printf("unable to open file %s\n", fn);
exit(0);
}
LRUHits = 0;
pLRUHits = 0;
randomHits = 0;
Cache *cache0 = new Cache(l, k, n, 0); // LRU
Cache *cache1 = new Cache(l, k, n, 1); // pseudoLRU
Cache *cache2 = new Cache(l, k, n, 2); // random
int bytes, word0, a, type, burstcount;
int hits = 0;
int tcount = 0;
while (bytes = read(tf, buf, sizeof(buf)))
{
for (int i = 0; i < bytes/(int) sizeof(trace); i++, tcount++)
{
word0 = buf[i].word0;
a = (word0 & ADDRESSMASK) << 2;
type = (word0 >> TYPESHIFT) & TYPEMASK;
burstcount = ((word0 >> BURSTSHIFT) & BURSTMASK) + 1;
cache0->hit(a);
cache1->hit(a);
cache2->hit(a);
}
}
printf("Hits: %d Total: %d\n", LRUHits, tcount);
printf("Hits: %d Total: %d\n", pLRUHits, tcount);
printf("Hits: %d Total: %d\n\n\n", randomHits, tcount);
delete cache0;
delete cache1;
delete cache2;
}
int _tmain(int argc, _TCHAR* argv[])
{
//analyse(16, 1, 8);
analyse(16, 2, 512);
//analyse(16, 4, 256);
//analyse(16, 8, 128);
//analyse(16, 1024, 1);
_getch();
return 0;
}
不會編譯:http://ideone.com/qCewp – elmo 2012-04-10 14:59:56
道歉。我只是將問題的具體功能包括在內 - 但當然,這還不足以繼續。抱歉! (現在有完整的代碼) – 2012-04-10 16:37:40