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我正在嘗試創建一個Google地圖,該地圖將顯示從地圖上的一個標記到2個或多個單獨標記的多個測地線。我可以在地圖上放置我的多個標記,但是我在解決如何從地圖上的一個標記中移除2個或更多路徑時遇到問題。目前,這是它是如何顯示谷歌地圖來自一個標記的多個測地線路
這裏是我的地圖
<script type="text/javascript" src="https://maps.googleapis.com/maps/api/js?sensor=false&libraries=geometry"></script>
<script type="text/javascript">
var geodesicPoly1;
var geodesicPoly2;
var marker1;
var marker2;
var marker3;
function initialize() {
var myOptions = {
zoom: 4,
center: new google.maps.LatLng(39.0997, -94.5786),
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById('map_canvas'), myOptions);
marker1 = new google.maps.Marker({
map: map,
draggable: false,
position: new google.maps.LatLng(33.7490, -84.3880)
});
marker2 = new google.maps.Marker({
map: map,
draggable: false,
position: new google.maps.LatLng(33.4484, -112.0740)
});
marker3 = new google.maps.Marker({
map: map,
draggable: false,
position: new google.maps.LatLng(37.9577, -121.2908)
});
var geodesicOptions = {
strokeColor: '#77bf44',
strokeOpacity: 1.0,
strokeWeight: 3,
geodesic: true,
map: map
};
geodesicPoly1 = new google.maps.Polyline(geodesicOptions);
update();
geodesicPoly2 = new google.maps.Polyline(geodesicOptions);
update2();
}
function update() {
var path = [marker1.getPosition(), marker2.getPosition()];
geodesicPoly1.setPath(path);
var heading = google.maps.geometry.spherical.computeHeading(path[0], path[1]);
document.getElementById('heading').value = heading;
document.getElementById('origin').value = path[0].toString();
document.getElementById('destination').value = path[1].toString();
}
function update2() {
var path = [marker1.getPosition(), marker3.getPosition()];
geodesicPoly2.setPath(path);
var heading = google.maps.geometry.spherical.computeHeading(path[0], path[1]);
document.getElementId('heading').value = heading;
document.getElementId('origin').value = path[0].toString();
document.getElementId('destination').value = path[1].toString();
}
google.maps.event.addDomListener(window, 'load', initialize);
</script>
我不知道在哪裏的問題是在你的代碼。我提供了我的整個代碼文件,它可以在IE和Chrome中使用。 –
謝謝傑克我通過註釋掉document.getElementId部分在我的代碼中工作。也許我在那裏有一個語法錯誤。感謝您的幫助和正確的解決方案。 –