我想通過使用帶有可編輯數據的模態來編輯數據。使用ajax在php中使用可編輯數據的Bootstrap模態
$HTML='<script> var js_array = '.JSON_encode($result).';
</script>';
echo $HTML;
,並在javascript
var id=supplier_id;
$.ajax({
url:"index.php/Supplier/edit",
type:"POST",
data:{ID:id},
dataType: 'json',
cache: false,
success: function(result) {
.............??????????????..................
alert(js_array['SupplierCode']);
},
});
}
現在我有JSON對象,但我想單獨訪問的對象,但它不工作。
我有以下格式我的數據:
var js_array = {"SupplierCode":"52","SupplierName":"GANE","Address":"79\/9 UR ST","City":"TANJORE","State":"TN","Country":"IN","PinCode":"624531","ContactPerson":"GANI","MobileNumber":"8807892105","TelephoneNumber":null,"EmailID":"[email protected]","FaxNumber":null,"Website":"www.gani.in"};
$ HTML =' - 文本必須被引用,因此等於雙引號單引號.PHP。單引號雙引號分號 – gibberish
@gibberish您能否將該評論置入回答問號 – jkdev
@gibberish仍然無法獲得警報以獲取對象。 ajax代碼中是否有錯誤?你能證實嗎? – mul1103