MySQL的GET字符串到左的字符，並與另一列

Question

我運行該SQL查詢

SELECT DISTINCT a.user_login, a.user_email, c.domain 
FROM wp_users a 
JOIN wp_usermeta b ON a.id = b.user_id 
JOIN wp_blogs c ON b.meta_value = c.site_id 
WHERE meta_key = 'primary_blog' and 
ORDER BY `a`.`ID` ASC 
LIMIT 0 , 100 

結果

user_login  user_email    domain 
abc    xys@example.com   laskdlasd.com 
cdestefano  cdestefano@example.com kaskdjkasjdkasd 
fran    fran@example.com   kasdllasdlasd 

我只想要其中USER_LOGIN不等於行比較到@之前的字符串，即從上面的結果我只需要下面的行

abc    xys@example.com   laskdlasd.com 

我試過下面的代碼，但它不能正常工作

SELECT DISTINCT a.user_login, a.user_email, c.domain 
FROM wp_users a 
JOIN wp_usermeta b ON a.id = b.user_id 
JOIN wp_blogs c ON b.meta_value = c.site_id 
WHERE meta_key = 'primary_blog' 
AND a.user_login != LEFT(a.user_email, LOCATE( '@', a.user_email)) 
ORDER BY `a`.`ID` ASC 
LIMIT 0 , 100 

如何得到想要的結果？

Answer 1

添加本就WHERE條款，

AND SUBSTRING(REPLACE(user_email, user_login, ''), 1, 1) <> '@' 

Answer 2

嘗試

SELECT * 
FROM wp_users a 
JOIN wp_usermeta b ON a.id = b.user_id 
JOIN wp_blogs c ON b.meta_value = c.site_id 
WHERE user_login != substring_index(user_email,'@',1)