我怎樣才能在巨蟒

Question

迴路並聯我有兩個列表

l1= [1,2,3,4,5,6,7] 
l2 = [1,2,3,4,5,6,7,8,9,77,66,] 

我想在同一行

顯示它們

"list1 text" "list2 text" 

l1-1 , l2-1 
l1-2 , l2-2 

等

所以如果列表元素那麼它應該在其前面顯示空白""，但另一側顯示其自己的元素，如

for a,b in l1,l2 
    <td>a</td><td> b </td> 

Answer 1

您可以使用izip_longest與空白的fillvalue，

>>> from itertools import izip_longest 
>>> for a,b in izip_longest(l1,l2,fillvalue=' '): 
...  print a,b 
... 
1 1 
2 2 
3 3 
4 4 
5 5 
6 6 
7 7 
    8 
    9 
    77 
    66 

Answer 2

像這樣的事情？

from itertools import izip_longest 
l1= [1,2,3,4,5,6,7] 
l2 = [1,2,3,4,5,6,7,8,9,77,66,] 

for a,b in izip_longest(l1,l2, fillvalue=''): 
    print '"'+str(a)+'"','"'+str(b)+'"' 

日期：

"1" "1" 
"2" "2" 
"3" "3" 
"4" "4" 
"5" "5" 
"6" "6" 
"7" "7" 
"" "8" 
"" "9" 
"" "77" 
"" "66" 

Answer 3

Itertools.izip_longest可以用來將兩個清單合併，該值都不會被用作「失蹤」，在較短的列表項的佔位符值。

Answer 4

>>>l1= [1,2,3,4,5,6,7] 
>>l2 = [1,2,3,4,5,6,7,8,9,77,66,] 
>>>n = ((a,b) for a in l1 for b in l2) 
>>>for i in n: 
     i 

瞭解更多詳情，請通過這個鏈接： Hidden features of Python

Answer 5

>>> l1= [1,2,3,4,5,6,7] 
>>> l2 = [1,2,3,4,5,6,7,8,9,77,66,] 
>>> def render_items(*args): 
...  return ''.join('<td>{}</td>'.format('' if i is None else i) for i in args) 
... 
>>> for item in map(render_items, l1, l2): 
...  print item 
... 
<td>1</td><td>1</td> 
<td>2</td><td>2</td> 
<td>3</td><td>3</td> 
<td>4</td><td>4</td> 
<td>5</td><td>5</td> 
<td>6</td><td>6</td> 
<td>7</td><td>7</td> 
<td></td><td>8</td> 
<td></td><td>9</td> 
<td></td><td>77</td> 
<td></td><td>66</td> 

Answer 6

l1= [1,2,3,4,5,6,7] 
l2 = [1,2,3,4,5,6,7,8,9,77,66] 
maxlen = max(len(l1),len(l2)) 
l1_ext = l1 + (maxlen-len(l1))*[' '] 
l2_ext = l2 + (maxlen-len(l2))*[' '] 
for (a,b) in zip(l1_ext,l2_ext): 
    print a,b 

Answer 7

l1= [1,2,3,4,5,6,7] 
l2 = [1,2,3,4,5,6,7,8,9,77,66] 
for (a,b) in map(lambda a,b:(a or ' ',b or ' '), l1, l2): 
    print a,b