-1
我想更新數據庫skadate_profile一行與此代碼MySQL的更新查詢 -
if (!isset($_COOKIE["lastlogin"]))
{
setcookie("lastlogin", $current_cookie, mktime(23, 59, 59, date("m"), date("d"), date("y")) , "/", "", 0);
$result8 = mysql_query("UPDATE skadate_profile SET time_left = 600, cookie = '".$current_cookie."',todays_date = '".$todays_date."' where profile_id = '".mysql_real_escape_string($avconfig['siteId'])."' limit 1");
$cook = $_COOKIE["lastlogin"]; //users PC cookie
//echo "RESULT ", $result8;
//echo "Here setting cookie to ", $cook;
} else {
//echo "Cookie was prev set and is ", $cook;
}
$ result8給出值1
有人能幫助我嗎?
爲什麼它應該給出與1不同的東西? –
問題是什麼?數據庫沒有更新指定的表嗎? – elimirks
'$ result8給出1的值是什麼意思?如果你的意思是它只給你一個結果,那是因爲'limit 1' –