JAXB編組子類繼承

我有一個將作爲根元素的對象（Department）。它有一個聚合對象（Employee），它有兩個專門化（Manager和FactoryWorker）。如果我將Employee設置爲其中一個專用對象，那麼只有Employee對象屬性被編組。我會很感激任何提示。JAXB編組子類繼承

例如

@XmlRootElement(name="department") 
class Department { 
    public Department() {} 
    private Employee employee; 
    public void setEmployee(final Employee val) { 
     this.employee = val; 
    } 
} 

class Employee { 
    private Long id; 
    public Employee() {} 
    //getters and setters 
} 

class Manager extends Employee { 
    public Manager() {} 
    private Integer numberOfProjects; 
    //getters and setters 
} 
class FactoryWorker extends Employee { 
    public FactoryWorker() {} 
    private Boolean worksNights; 
    //getters and setters 
}

的代碼片段只顯示編組

Deparment department = new Department(); 
FactoryWorker factoryWorker = new FactoryWorker(); 
factoryWorker.setId(999); 
factoryWorker.setWorksNights(true); 

JAXBContext jaxBContext = JAXBContext.newInstance(Department.class); 
Marshaller jaxbMarshaller = jaxBContext.createMarshaller(); 
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true); 
jaxbMarshaller.marshal(department, System.out);

JAXB輸出：工廠工人的專業屬性不存在。只是父Employee中的值。

<department> 
    <employee> 
     <id>999</id> 
    </employee> 
</department>

來源

2015-05-13 solarwind

有辦法在代碼中錯別字太多，你粘貼 –

手寫代碼簡單地代表了一個簡單的父母/孩子結構與標準簡le getters和setter。無論如何，我已經更新了它。 – solarwind

你需要做的是這樣的：

將輸出

@XmlRootElement(name="Department") 
class Department { 
    public Department() {} 
    @XmlElements({ 
     @XmlElement(name="Manager", type=Manager.class), 
     @XmlElement(name="FactoryWorker", type=FactoryWorker.class) 
    }) 
    private Employee employee; 
    public void setEmployee(Employee val) {this.employee = val;} 
}

：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> 
<Department> 
    <FactoryWorker> 
     <id>999</id> 
     <worksNights>true</worksNights> 
    </FactoryWorker> 
</Department>

演示：

來源

2015-05-13 15:10:41

感謝Guido。完善。 – solarwind

歡迎你;只是爲了挑剔你的代碼，你可能希望在JAXBContext.newInstance（）調用中添加子類作爲附加參數。我記得（不知道）我從註釋類生成模式時必須這樣做。 –

謝謝答案我也面臨同樣的問題。現在我需要unmarshal這個XML，但我geting異常像 com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException：1計數IllegalAnnotationExceptions 類有兩個同名「Person」的屬性 –

JAXB編組子類繼承

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