2016-08-11 82 views
0

我正在嘗試使用快速站點地圖中間件爲我的網站生成站點地圖。我的代碼如下:(Node/Express)快速站點地圖生成不正確的站點地圖

var sitemap = require('express-sitemap')(); 
//... 
app.get('/', function(req, res) { 
    res.render('index') 
}) 
//... 
posts = [ 
    post2 = { 
    "url": 
    "wild-birds", 
    },  
    post1 = { 
    "url": 
    "top-dogs-cats", 
    } 
] 

app.get('/:leg', function(req, res, next) { 
    for (i=0; i<posts.length; i++) { 
     if (req.params.leg == posts[i].url) { 
      res.render('post', { posts2:posts[i] }); 
     } 
    } 
//The above code checks to see which blog post was requested by 
//the user, and responds by rendering the associated HTML (with some 
//additional information I chose to exclude from this post) 
}) 

console.log(sitemap.generate(app)) 

此輸出:

{ '/': [ 'get' ], 
    '/:leg': [ 'get' ] } 

當它應該是輸出:

{ '/': [ 'get' ], 
    '/wild-birds': [ 'get' ], 
    '/top-dogs-cats': [ 'get' ] 
} 

我應該如何去解決這個網站地圖生成器?此外,你會如何建議將更正的sitemap.xml提供給用戶?

回答

1

express-sitemap遍歷所有註冊的路由以生成站點地圖。它在內部呼叫:app._router.stack,然後過濾所有路由。

您應該明確註冊您的帖子作爲路線,而不是使用參數。做到這一點,而不是:

posts.forEach(function(post) { 
    app.get('/' + post.url, function(req, res, next) { 
    res.render('post', { 
     posts2: post 
    }); 
    // your logic... 
    }); 
}); 

然後調用console.log(sitemap.generate(app))返回你所期望:

{ '/': [ 'get' ], 
    '/wild-birds': [ 'get' ], 
    '/top-dogs-cats': [ 'get' ] }